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# [2169. Count Operations to Obtain Zero](https://leetcode.com/problems/count-operations-to-obtain-zero/)
## 题目
You are given two **non-negative** integers `num1` and `num2`.
In one **operation**, if `num1 >= num2`, you must subtract `num2` from `num1`, otherwise subtract `num1` from `num2`.
- For example, if `num1 = 5` and `num2 = 4`, subtract `num2` from `num1`, thus obtaining `num1 = 1` and `num2 = 4`. However, if `num1 = 4` and `num2 = 5`, after one operation, `num1 = 4` and `num2 = 1`.
Return *the **number of operations** required to make either* `num1 = 0` *or* `num2 = 0`.
**Example 1:**
```
Input: num1 = 2, num2 = 3
Output: 3
Explanation:
- Operation 1: num1 = 2, num2 = 3. Since num1 < num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1.
- Operation 2: num1 = 2, num2 = 1. Since num1 > num2, we subtract num2 from num1.
- Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1.
Now num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations.
So the total number of operations required is 3.
```
**Example 2:**
```
Input: num1 = 10, num2 = 10
Output: 1
Explanation:
- Operation 1: num1 = 10, num2 = 10. Since num1 == num2, we subtract num2 from num1 and get num1 = 10 - 10 = 0.
Now num1 = 0 and num2 = 10. Since num1 == 0, we are done.
So the total number of operations required is 1.
```
**Constraints:**
- `0 <= num1, num2 <= 10^5`
## 题目大意
给你两个 非负 整数 num1 和 num2 。每一步 操作 中,如果 num1 >= num2 ,你必须用 num1 减 num2 ;否则,你必须用 num2 减 num1 。
- 例如num1 = 5 且 num2 = 4 应该用 num1 减 num2 ,因此,得到 num1 = 1 和 num2 = 4 。然而,如果 num1 = 4且 num2 = 5 ,一步操作后,得到 num1 = 4 和 num2 = 1 。
返回使 num1 = 0 或 num2 = 0 的 操作数 。
## 解题思路
- 简单题,按照题意模拟,每次两个数字相减,便累加操作次数。当某个数字变为 0 时,输出操作次数。
## 代码
```go
package leetcode
func countOperations(num1 int, num2 int) int {
res := 0
for num1 != 0 && num2 != 0 {
if num1 >= num2 {
num1 -= num2
} else {
num2 -= num1
}
res++
}
return res
}
```