mirror of
https://github.com/halfrost/LeetCode-Go.git
synced 2025-07-07 18:10:29 +08:00
86 lines
2.9 KiB
Markdown
86 lines
2.9 KiB
Markdown
# [495. Teemo Attacking](https://leetcode.com/problems/teemo-attacking/)
|
||
|
||
|
||
## 题目
|
||
|
||
Our hero Teemo is attacking an enemy Ashe with poison attacks! When Teemo attacks Ashe, Ashe gets poisoned for a exactly duration seconds.
|
||
|
||
More formally, an attack at second t will mean Ashe is poisoned during the inclusive time interval [t, t + duration - 1].
|
||
|
||
If Teemo attacks again before the poison effect ends, the timer for it is reset, and the poison effect will end duration seconds after the new attack.
|
||
|
||
You are given a non-decreasing integer array timeSeries, where timeSeries[i] denotes that Teemo attacks Ashe at second timeSeries[i], and an integer duration.
|
||
|
||
Return the total number of seconds that Ashe is poisoned.
|
||
|
||
**Example 1**:
|
||
```
|
||
Input: timeSeries = [1,4], duration = 2
|
||
Output: 4
|
||
Explanation: Teemo's attacks on Ashe go as follows:
|
||
- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
|
||
- At second 4, Teemo attacks, and Ashe is poisoned for seconds 4 and 5.
|
||
Ashe is poisoned for seconds 1, 2, 4, and 5, which is 4 seconds in total.
|
||
```
|
||
|
||
**Example 2**:
|
||
```
|
||
Input: timeSeries = [1,2], duration = 2
|
||
Output: 3
|
||
Explanation: Teemo's attacks on Ashe go as follows:
|
||
- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
|
||
- At second 2 however, Teemo attacks again and resets the poison timer. Ashe is poisoned for seconds 2 and 3.
|
||
Ashe is poisoned for seconds 1, 2, and 3, which is 3 seconds in total.
|
||
```
|
||
|
||
**Constraints**:
|
||
|
||
- 1 <= timeSeries.length <= 10000
|
||
- 0 <= timeSeries[i], duration <= 10000000
|
||
- timeSeries is sorted in non-decreasing order.
|
||
|
||
## 题目大意
|
||
|
||
在《英雄联盟》的世界中,有一个叫 “提莫” 的英雄。他的攻击可以让敌方英雄艾希(编者注:寒冰射手)进入中毒状态。
|
||
|
||
当提莫攻击艾希,艾希的中毒状态正好持续duration 秒。
|
||
|
||
正式地讲,提莫在t发起发起攻击意味着艾希在时间区间 [t, t + duration - 1](含 t 和 t + duration - 1)处于中毒状态。
|
||
|
||
如果提莫在中毒影响结束前再次攻击,中毒状态计时器将会重置,在新的攻击之后,中毒影响将会在duration秒后结束。
|
||
|
||
给你一个非递减的整数数组timeSeries,其中timeSeries[i]表示提莫在timeSeries[i]秒时对艾希发起攻击,以及一个表示中毒持续时间的整数duration 。
|
||
|
||
返回艾希处于中毒状态的总秒数。
|
||
|
||
## 解题思路
|
||
|
||
- i 从 1 开始计数,令 t 等于 timeSeries[i - 1]
|
||
- 比较 end(t + duration - 1) 和 timeSeries[i] 的大小,
|
||
- 如果 end 小于 timeSeries[i],ans+=duration
|
||
- 否则 ans += timeSeries[i] - t
|
||
- ans += duration 并返回 ans
|
||
|
||
## 代码
|
||
|
||
```go
|
||
|
||
package leetcode
|
||
|
||
func findPoisonedDuration(timeSeries []int, duration int) int {
|
||
var ans int
|
||
for i := 1; i < len(timeSeries); i++ {
|
||
t := timeSeries[i-1]
|
||
end := t + duration - 1
|
||
if end < timeSeries[i] {
|
||
ans += duration
|
||
} else {
|
||
ans += timeSeries[i] - t
|
||
}
|
||
}
|
||
ans += duration
|
||
return ans
|
||
}
|
||
|
||
```
|