mirror of
https://github.com/halfrost/LeetCode-Go.git
synced 2025-07-05 16:36:41 +08:00
40 lines
1.3 KiB
Markdown
40 lines
1.3 KiB
Markdown
# [237. Delete Node in a Linked List](https://leetcode.com/problems/delete-node-in-a-linked-list/)
|
||
|
||
## 题目
|
||
|
||
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
|
||
|
||
Given linked list -- head = [4,5,1,9], which looks like following:
|
||
|
||
|
||
|
||
Example 1:
|
||
|
||
```c
|
||
Input: head = [4,5,1,9], node = 5
|
||
Output: [4,1,9]
|
||
Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.
|
||
```
|
||
|
||
Example 2:
|
||
|
||
```c
|
||
Input: head = [4,5,1,9], node = 1
|
||
Output: [4,5,9]
|
||
Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.
|
||
```
|
||
|
||
Note:
|
||
|
||
- The linked list will have at least two elements.
|
||
- All of the nodes' values will be unique.
|
||
- The given node will not be the tail and it will always be a valid node of the linked list.
|
||
- Do not return anything from your function.
|
||
|
||
## 题目大意
|
||
|
||
删除给点结点。没有给链表的头结点。
|
||
|
||
## 解题思路
|
||
|
||
其实就是把后面的结点都覆盖上来即可。或者直接当前结点的值等于下一个结点，Next 指针指向下下个结点，这样做也可以，只不过中间有一个结点不被释放，内存消耗多一些。 |