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@ -81,5 +81,5 @@ func nextGreaterElements1(nums []int) []int {
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# [504. Base 7](https://leetcode.com/problems/base-7/)
## 题目
Given an integer num, return a string of its base 7 representation.
**Example 1:**
Input: num = 100
Output: "202"
**Example 2:**
Input: num = -7
Output: "-10"
**Constraints:**
- -10000000 <= num <= 10000000
## 题目大意
给定一个整数 num将其转化为 7 进制,并以字符串形式输出。
## 解题思路
num反复除以7然后倒排余数
# 代码
```go
package leetcode
import "strconv"
func convertToBase7(num int) string {
if num == 0 {
return "0"
}
negative := false
if num < 0 {
negative = true
num = -num
}
var ans string
var nums []int
for num != 0 {
remainder := num % 7
nums = append(nums, remainder)
num = num / 7
}
if negative {
ans += "-"
}
for i := len(nums) - 1; i >= 0; i-- {
ans += strconv.Itoa(nums[i])
}
return ans
}
```
----------------------------------------------
<div style="display: flex;justify-content: space-between;align-items: center;">
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@ -86,6 +86,6 @@ func findRelativeRanks(score []int) []string {
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@ -113,6 +113,7 @@ func dfs(board [][]byte, x, y int) {
nx, ny := x+dir8[i][0], y+dir8[i][1]
if isInBoard(board, nx, ny) && board[nx][ny] == 'M' {
cnt++
}
}
if cnt > 0 {
@ -133,6 +134,7 @@ func isInBoard(board [][]byte, x, y int) bool {
}
```
----------------------------------------------
<div style="display: flex;justify-content: space-between;align-items: center;">
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@ -189,5 +189,5 @@ func isLowerLetter(v byte) bool {
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# [728. Self Dividing Numbers](https://leetcode.com/problems/self-dividing-numbers/)
## 题目
A self-dividing number is a number that is divisible by every digit it contains.
- For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0.
A self-dividing number is not allowed to contain the digit zero.
Given two integers left and right, return a list of all the self-dividing numbers in the range [left, right].
**Example 1:**
Input: left = 1, right = 22
Output: [1,2,3,4,5,6,7,8,9,11,12,15,22]
**Example 2:**
Input: left = 47, right = 85
Output: [48,55,66,77]
**Constraints:**
- 1 <= left <= right <= 10000
## 题目大意
自除数是指可以被它包含的每一位数整除的数。
- 例如128 是一个 自除数 ,因为 128 % 1 == 0128 % 2 == 0128 % 8 == 0。
自除数 不允许包含 0 。
给定两个整数 left 和 right ,返回一个列表,列表的元素是范围 [left, right] 内所有的 自除数 。
## 解题思路
- 模拟计算
# 代码
```go
package leetcode
func selfDividingNumbers(left int, right int) []int {
var ans []int
for num := left; num <= right; num++ {
if selfDividingNum(num) {
ans = append(ans, num)
}
}
return ans
}
func selfDividingNum(num int) bool {
for d := num; d > 0; d = d / 10 {
reminder := d % 10
if reminder == 0 {
return false
}
if num%reminder != 0 {
return false
}
}
return true
}
```
----------------------------------------------
<div style="display: flex;justify-content: space-between;align-items: center;">
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@ -182,6 +182,6 @@ func (this *MyCalendar) Book(start int, end int) bool {
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@ -80,5 +80,5 @@ func construct2DArray(original []int, m int, n int) [][]int {
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# [2037. Minimum Number of Moves to Seat Everyone](https://leetcode.com/problems/minimum-number-of-moves-to-seat-everyone/)
## 题目
There are n seats and n students in a room. You are given an array seats of length n, where seats[i] is the position of the ith seat. You are also given the array students of length n, where students[j] is the position of the jth student.
You may perform the following move any number of times:
- Increase or decrease the position of the ith student by 1 (i.e., moving the ith student from position x to x + 1 or x - 1)
Return the minimum number of moves required to move each student to a seat such that no two students are in the same seat.
Note that there may be multiple seats or students in the same position at the beginning.
**Example 1:**
Input: seats = [3,1,5], students = [2,7,4]
Output: 4
Explanation: The students are moved as follows:
- The first student is moved from from position 2 to position 1 using 1 move.
- The second student is moved from from position 7 to position 5 using 2 moves.
- The third student is moved from from position 4 to position 3 using 1 move.
In total, 1 + 2 + 1 = 4 moves were used.
**Example 2:**
Input: seats = [4,1,5,9], students = [1,3,2,6]
Output: 7
Explanation: The students are moved as follows:
- The first student is not moved.
- The second student is moved from from position 3 to position 4 using 1 move.
- The third student is moved from from position 2 to position 5 using 3 moves.
- The fourth student is moved from from position 6 to position 9 using 3 moves.
In total, 0 + 1 + 3 + 3 = 7 moves were used.
**Example 3:**
Input: seats = [2,2,6,6], students = [1,3,2,6]
Output: 4
Explanation: Note that there are two seats at position 2 and two seats at position 6.
The students are moved as follows:
- The first student is moved from from position 1 to position 2 using 1 move.
- The second student is moved from from position 3 to position 6 using 3 moves.
- The third student is not moved.
- The fourth student is not moved.
In total, 1 + 3 + 0 + 0 = 4 moves were used.
**Constraints:**
- n == seats.length == students.length
- 1 <= n <= 100
- 1 <= seats[i], students[j] <= 100
## 题目大意
一个房间里有 n 个座位和 n 名学生,房间用一个数轴表示。给你一个长度为 n 的数组 seats其中 seats[i] 是第 i 个座位的位置。同时给你一个长度为 n 的数组 students ,其中 students[j] 是第 j 位学生的位置。
你可以执行以下操作任意次:
增加或者减少第 i 位学生的位置,每次变化量为 1也就是将第 i 位学生从位置 x 移动到 x + 1或者 x - 1
请你返回使所有学生都有座位坐的最少移动次数,并确保没有两位学生的座位相同。
请注意,初始时有可能有多个座位或者多位学生在 同一位置。
## 解题思路
- 排序+模拟计算
# 代码
```go
package leetcode
import "sort"
func minMovesToSeat(seats []int, students []int) int {
sort.Ints(seats)
sort.Ints(students)
n := len(students)
moves := 0
for i := 0; i < n; i++ {
moves += abs(seats[i], students[i])
}
return moves
}
func abs(a, b int) int {
if a > b {
return a - b
}
return b - a
}
```
----------------------------------------------
<div style="display: flex;justify-content: space-between;align-items: center;">
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# [2038. Remove Colored Pieces if Both Neighbors are the Same Color](https://leetcode.com/problems/remove-colored-pieces-if-both-neighbors-are-the-same-color/)
## 题目
There are n pieces arranged in a line, and each piece is colored either by 'A' or by 'B'. You are given a string colors of length n where colors[i] is the color of the ith piece.
Alice and Bob are playing a game where they take alternating turns removing pieces from the line. In this game, Alice moves first.
- Alice is only allowed to remove a piece colored 'A' if both its neighbors are also colored 'A'. She is not allowed to remove pieces that are colored 'B'.
- Bob is only allowed to remove a piece colored 'B' if both its neighbors are also colored 'B'. He is not allowed to remove pieces that are colored 'A'.
- Alice and Bob cannot remove pieces from the edge of the line.
- If a player cannot make a move on their turn, that player loses and the other player wins.
Assuming Alice and Bob play optimally, return true if Alice wins, or return false if Bob wins.
**Example 1:**
Input: colors = "AAABABB"
Output: true
Explanation:
AAABABB -> AABABB
Alice moves first.
She removes the second 'A' from the left since that is the only 'A' whose neighbors are both 'A'.
Now it's Bob's turn.
Bob cannot make a move on his turn since there are no 'B's whose neighbors are both 'B'.
Thus, Alice wins, so return true.
**Example 2:**
Input: colors = "AA"
Output: false
Explanation:
Alice has her turn first.
There are only two 'A's and both are on the edge of the line, so she cannot move on her turn.
Thus, Bob wins, so return false.
**Example 3:**
Input: colors = "ABBBBBBBAAA"
Output: false
Explanation:
ABBBBBBBAAA -> ABBBBBBBAA
Alice moves first.
Her only option is to remove the second to last 'A' from the right.
ABBBBBBBAA -> ABBBBBBAA
Next is Bob's turn.
He has many options for which 'B' piece to remove. He can pick any.
On Alice's second turn, she has no more pieces that she can remove.
Thus, Bob wins, so return false.
**Constraints:**
- 1 <= colors.length <= 100000
- colors consists of only the letters 'A' and 'B'
## 题目大意
总共有 n 个颜色片段排成一列,每个颜色片段要么是 'A' 要么是 'B' 。给你一个长度为 n 的字符串 colors ,其中 colors[i] 表示第 i 个颜色片段的颜色。
Alice 和 Bob 在玩一个游戏他们轮流从这个字符串中删除颜色。Alice 先手。
- 如果一个颜色片段为 'A' 且相邻两个颜色都是颜色 'A',那么 Alice 可以删除该颜色片段。Alice不可以删除任何颜色 'B' 片段。
- 如果一个颜色片段为 'B'且相邻两个颜色都是颜色 'B' ,那么 Bob 可以删除该颜色片段。Bob 不可以删除任何颜色 'A' 片段。
- Alice 和 Bob 不能从字符串两端删除颜色片段。
- 如果其中一人无法继续操作,则该玩家 输掉游戏且另一玩家 获胜。
假设 Alice 和 Bob 都采用最优策略,如果 Alice 获胜请返回true否则 Bob 获胜返回false。
## 解题思路
- 统计 Alice 和 Bob 分别可以操作的次数记为 AsBs
- 因为 Alice 先手,所以只要 As 大于 BsAlice 获胜返回 true否则 Bob 获胜返回 false
# 代码
```go
package leetcode
func winnerOfGame(colors string) bool {
As, Bs := 0, 0
Acont, Bcont := 0, 0
for _, color := range colors {
if color == 'A' {
Acont += 1
Bcont = 0
} else {
Bcont += 1
Acont = 0
}
if Acont >= 3 {
As += Acont - 2
}
if Bcont >= 3 {
Bs += Bcont - 2
}
}
if As > Bs {
return true
}
return false
}
```
----------------------------------------------
<div style="display: flex;justify-content: space-between;align-items: center;">
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# [2043. Simple Bank System](https://leetcode.com/problems/simple-bank-system/)
## 题目
You have been tasked with writing a program for a popular bank that will automate all its incoming transactions (transfer, deposit, and withdraw). The bank has n accounts numbered from 1 to n. The initial balance of each account is stored in a 0-indexed integer array balance, with the (i + 1)th account having an initial balance of balance[i].
Execute all the valid transactions. A transaction is valid if:
- The given account number(s) are between 1 and n, and
- The amount of money withdrawn or transferred from is less than or equal to the balance of the account.
Implement the Bank class:
- Bank(long[] balance) Initializes the object with the 0-indexed integer array balance.
- boolean transfer(int account1, int account2, long money) Transfers money dollars from the account numbered account1 to the account numbered account2. Return true if the transaction was successful, false otherwise.
- boolean deposit(int account, long money) Deposit money dollars into the account numbered account. Return true if the transaction was successful, false otherwise.
- boolean withdraw(int account, long money) Withdraw money dollars from the account numbered account. Return true if the transaction was successful, false otherwise.
**Example 1:**
Input
["Bank", "withdraw", "transfer", "deposit", "transfer", "withdraw"]
[[[10, 100, 20, 50, 30]], [3, 10], [5, 1, 20], [5, 20], [3, 4, 15], [10, 50]]
Output
[null, true, true, true, false, false]
Explanation
Bank bank = new Bank([10, 100, 20, 50, 30]);
bank.withdraw(3, 10); // return true, account 3 has a balance of $20, so it is valid to withdraw $10.
// Account 3 has $20 - $10 = $10.
bank.transfer(5, 1, 20); // return true, account 5 has a balance of $30, so it is valid to transfer $20.
// Account 5 has $30 - $20 = $10, and account 1 has $10 + $20 = $30.
bank.deposit(5, 20); // return true, it is valid to deposit $20 to account 5.
// Account 5 has $10 + $20 = $30.
bank.transfer(3, 4, 15); // return false, the current balance of account 3 is $10,
// so it is invalid to transfer $15 from it.
bank.withdraw(10, 50); // return false, it is invalid because account 10 does not exist.
**Constraints:**
- n == balance.length
- 1 <= n, account, account1, account2 <= 100000
- 0 <= balance[i], money <= 1000000000000
- At most 104 calls will be made to each function transfer, deposit, withdraw.
## 题目大意
你的任务是为一个很受欢迎的银行设计一款程序,以自动化执行所有传入的交易(转账,存款和取款)。银行共有 n 个账户,编号从 1 到 n 。每个账号的初始余额存储在一个下标从 0 开始的整数数组 balance 中,其中第 (i + 1) 个账户的初始余额是 balance[i] 。
请你执行所有 有效的 交易。如果满足下面全部条件,则交易 有效
- 指定的账户数量在 1 和 n 之间,且
- 取款或者转账需要的钱的总数 小于或者等于 账户余额。
实现 Bank 类:
- Bank(long[] balance) 使用下标从 0 开始的整数数组 balance 初始化该对象。
- boolean transfer(int account1, int account2, long money) 从编号为 account1 的账户向编号为 account2 的账户转帐 money 美元。如果交易成功,返回 true ,否则,返回 false 。
- boolean deposit(int account, long money) 向编号为 account 的账户存款 money 美元。如果交易成功,返回 true ;否则,返回 false 。
- boolean withdraw(int account, long money) 从编号为 account 的账户取款 money 美元。如果交易成功,返回 true ;否则,返回 false 。
## 解题思路
根据题意进行简单模拟
# 代码
```go
package leetcode
type Bank struct {
accounts []int64
n int
}
func Constructor(balance []int64) Bank {
return Bank{
accounts: balance,
n: len(balance),
}
}
func (this *Bank) Transfer(account1 int, account2 int, money int64) bool {
if account1 > this.n || account2 > this.n {
return false
}
if this.accounts[account1-1] < money {
return false
}
this.accounts[account1-1] -= money
this.accounts[account2-1] += money
return true
}
func (this *Bank) Deposit(account int, money int64) bool {
if account > this.n {
return false
}
this.accounts[account-1] += money
return true
}
func (this *Bank) Withdraw(account int, money int64) bool {
if account > this.n {
return false
}
if this.accounts[account-1] < money {
return false
}
this.accounts[account-1] -= money
return true
}
```
----------------------------------------------
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@ -95,6 +95,6 @@ func sortEvenOdd(nums []int) []int {
----------------------------------------------
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