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添加 problem 328
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package leetcode
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/**
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* Definition for singly-linked list.
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* type ListNode struct {
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* Val int
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* Next *ListNode
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* }
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*/
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func oddEvenList(head *ListNode) *ListNode {
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oddHead := &ListNode{Val: 0, Next: nil}
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odd := oddHead
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evenHead := &ListNode{Val: 0, Next: nil}
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even := evenHead
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count := 1
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for head != nil {
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if count%2 == 1 {
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odd.Next = head
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odd = odd.Next
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} else {
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even.Next = head
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even = even.Next
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}
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head = head.Next
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count++
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}
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even.Next = nil
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odd.Next = evenHead.Next
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return oddHead.Next
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}
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package leetcode
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import (
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"fmt"
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"testing"
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)
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type question328 struct {
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para328
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ans328
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}
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// para 是参数
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// one 代表第一个参数
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type para328 struct {
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one []int
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}
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// ans 是答案
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// one 代表第一个答案
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type ans328 struct {
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one []int
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}
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func Test_Problem328(t *testing.T) {
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qs := []question328{
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question328{
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para328{[]int{1, 4, 3, 2, 5, 2}},
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ans328{[]int{1, 3, 5, 4, 2, 2}},
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},
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question328{
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para328{[]int{1, 1, 2, 2, 3, 3, 3}},
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ans328{[]int{1, 2, 3, 3, 1, 2, 3}},
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},
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question328{
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para328{[]int{4, 3, 2, 5, 2}},
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ans328{[]int{4, 2, 2, 3, 5}},
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},
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question328{
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para328{[]int{1, 1, 1, 1, 1, 1}},
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ans328{[]int{1, 1, 1, 1, 1, 1}},
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},
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question328{
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para328{[]int{3, 1}},
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ans328{[]int{3, 1}},
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},
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question328{
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para328{[]int{1, 2, 3, 4, 5}},
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ans328{[]int{1, 3, 5, 2, 4}},
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},
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question328{
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para328{[]int{}},
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ans328{[]int{}},
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},
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}
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fmt.Printf("------------------------Leetcode Problem 328------------------------\n")
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for _, q := range qs {
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_, p := q.ans328, q.para328
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fmt.Printf("【input】:%v 【output】:%v\n", p, L2s(oddEvenList(S2l(p.one))))
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}
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fmt.Printf("\n\n\n")
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}
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30
Algorithms/328. Odd Even Linked List/README.md
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30
Algorithms/328. Odd Even Linked List/README.md
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# [328. Odd Even Linked List](https://leetcode.com/problems/odd-even-linked-list/)
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## 题目
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Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes.
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You should try to do it in place. The program should run in O(1) space complexity and O(nodes) time complexity.
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Example 1:
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```c
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Input: 1->2->3->4->5->NULL
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Output: 1->3->5->2->4->NULL
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```
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Example 2:
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```c
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Input: 2->1->3->5->6->4->7->NULL
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Output: 2->3->6->7->1->5->4->NULL
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```
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Note:
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- The relative order inside both the even and odd groups should remain as it was in the input.
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- The first node is considered odd, the second node even and so on ...
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## 题目大意
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这道题和第 86 题非常类型。第 86 题是把排在某个点前面的小值放在一个链表中,排在某个点后端的大值放在另外一个链表中,最后 2 个链表首尾拼接一下就是答案。这道题思路也是一样的,分别把奇数和偶数都放在 2 个链表中,最后首尾拼接就是答案。
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