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https://github.com/halfrost/LeetCode-Go.git
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添加 problem 350
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package leetcode
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func intersect(nums1 []int, nums2 []int) []int {
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m := map[int]int{}
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var res []int
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for _, n := range nums1 {
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m[n]++
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}
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for _, n := range nums2 {
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if m[n] > 0 {
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res = append(res, n)
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m[n]--
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}
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}
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return res
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}
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package leetcode
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import (
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"fmt"
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"testing"
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)
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type question350 struct {
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para350
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ans350
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}
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// para 是参数
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// one 代表第一个参数
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type para350 struct {
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one []int
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another []int
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}
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// ans 是答案
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// one 代表第一个答案
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type ans350 struct {
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one []int
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}
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func Test_Problem350(t *testing.T) {
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qs := []question350{
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question350{
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para350{[]int{}, []int{}},
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ans350{[]int{}},
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},
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question350{
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para350{[]int{1}, []int{1}},
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ans350{[]int{1}},
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},
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question350{
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para350{[]int{1, 2, 3, 4}, []int{1, 2, 3, 4}},
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ans350{[]int{1, 2, 3, 4}},
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},
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question350{
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para350{[]int{1, 2, 2, 1}, []int{2, 2}},
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ans350{[]int{2, 2}},
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},
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question350{
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para350{[]int{1}, []int{9, 9, 9, 9, 9}},
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ans350{[]int{}},
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},
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question350{
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para350{[]int{4, 9, 5}, []int{9, 4, 9, 8, 4}},
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ans350{[]int{9, 4}},
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},
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question350{
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para350{[]int{4, 9, 5, 9, 4}, []int{9, 4, 9, 8, 4, 7, 9, 4, 4, 9}},
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ans350{[]int{9, 4, 9, 4}},
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},
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// 如需多个测试,可以复制上方元素。
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}
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fmt.Printf("------------------------Leetcode Problem 350------------------------\n")
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for _, q := range qs {
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_, p := q.ans350, q.para350
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fmt.Printf("【input】:%v 【output】:%v\n", p, intersect(p.one, p.another))
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}
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fmt.Printf("\n\n\n")
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}
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42
Algorithms/350. Intersection of Two Arrays II/README.md
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42
Algorithms/350. Intersection of Two Arrays II/README.md
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# [350. Intersection of Two Arrays II](https://leetcode.com/problems/intersection-of-two-arrays-ii/)
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## 题目
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Given two arrays, write a function to compute their intersection.
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Example 1:
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```c
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Input: nums1 = [1,2,2,1], nums2 = [2,2]
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Output: [2,2]
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```
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Example 2:
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```c
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Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
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Output: [4,9]
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```
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Note:
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- Each element in the result should appear as many times as it shows in both arrays.
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- The result can be in any order.
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Follow up:
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- What if the given array is already sorted? How would you optimize your algorithm?
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- What if nums1's size is small compared to nums2's size? Which algorithm is better?
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- What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?
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## 题目大意
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这题是第 349 题的加强版。要求输出 2 个数组的交集元素,如果元素出现多次,要输出多次。
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这一题还是延续第 349 题的思路。把数组一中的数字都放进字典中,另外字典的 key 是数组中的数字,value 是这个数字出现的次数。在扫描数组二的时候,每取出一个存在的数组,把字典中的 value 减一。如果 value 是 0 代表不存在这个数字。
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