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添加 problem 101
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16
Algorithms/101. Symmetric Tree/101. Symmetric Tree.go
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16
Algorithms/101. Symmetric Tree/101. Symmetric Tree.go
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package leetcode
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/**
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* Definition for a binary tree node.
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* type TreeNode struct {
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* Val int
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* Left *TreeNode
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* Right *TreeNode
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* }
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*/
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func isSymmetric(root *TreeNode) bool {
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if root == nil {
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return true
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}
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return isSameTree(invertTree(root.Left), root.Right)
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}
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74
Algorithms/101. Symmetric Tree/101. Symmetric Tree_test.go
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74
Algorithms/101. Symmetric Tree/101. Symmetric Tree_test.go
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package leetcode
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import (
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"fmt"
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"testing"
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)
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type question101 struct {
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para101
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ans101
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}
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// para 是参数
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// one 代表第一个参数
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type para101 struct {
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one []int
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}
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// ans 是答案
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// one 代表第一个答案
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type ans101 struct {
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one bool
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}
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func Test_Problem101(t *testing.T) {
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qs := []question101{
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question101{
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para101{[]int{3, 4, 4, 5, NULL, NULL, 5, 6, NULL, NULL, 6}},
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ans101{true},
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},
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question101{
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para101{[]int{1, 2, 2, NULL, 3, 3}},
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ans101{true},
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},
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question101{
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para101{[]int{}},
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ans101{true},
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},
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question101{
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para101{[]int{1}},
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ans101{true},
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},
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question101{
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para101{[]int{1, 2, 3}},
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ans101{false},
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},
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question101{
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para101{[]int{1, 2, 2, 3, 4, 4, 3}},
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ans101{true},
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},
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question101{
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para101{[]int{1, 2, 2, NULL, 3, NULL, 3}},
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ans101{false},
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},
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}
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fmt.Printf("------------------------Leetcode Problem 101------------------------\n")
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for _, q := range qs {
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_, p := q.ans101, q.para101
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fmt.Printf("【input】:%v ", p)
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rootOne := Ints2TreeNode(p.one)
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fmt.Printf("【output】:%v \n", isSymmetric(rootOne))
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}
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fmt.Printf("\n\n\n")
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}
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39
Algorithms/101. Symmetric Tree/README.md
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39
Algorithms/101. Symmetric Tree/README.md
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# [101. Symmetric Tree](https://leetcode.com/problems/symmetric-tree/)
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## 题目
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Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
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For example, this binary tree [1,2,2,3,4,4,3] is symmetric:
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```c
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1
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/ \
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2 2
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/ \ / \
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3 4 4 3
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```
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But the following [1,2,2,null,3,null,3] is not:
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```c
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1
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/ \
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2 2
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\ \
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3 3
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```
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Note:
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Bonus points if you could solve it both recursively and iteratively.
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## 题目大意
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这一题要求判断 2 颗树是否是左右对称的。这道题是几道题的综合题。将根节点的左字数反转二叉树,然后再和根节点的右节点进行比较,是否完全相等。
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反转二叉树是第 226 题。判断 2 颗树是否完全相等是第 100 题。
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