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添加 problem 1184
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package leetcode
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func distanceBetweenBusStops(distance []int, start int, destination int) int {
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clockwiseDis, counterclockwiseDis, n := 0, 0, len(distance)
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for i := start; i != destination; i = (i + 1) % n {
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clockwiseDis += distance[i]
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}
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for i := destination; i != start; i = (i + 1) % n {
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counterclockwiseDis += distance[i]
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}
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if clockwiseDis < counterclockwiseDis {
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return clockwiseDis
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}
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return counterclockwiseDis
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}
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package leetcode
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import (
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"fmt"
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"testing"
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)
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type question1184 struct {
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para1184
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ans1184
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}
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// para 是参数
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// one 代表第一个参数
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type para1184 struct {
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distance []int
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start int
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destination int
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}
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// ans 是答案
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// one 代表第一个答案
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type ans1184 struct {
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one int
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}
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func Test_Problem1184(t *testing.T) {
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qs := []question1184{
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question1184{
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para1184{[]int{1, 2, 3, 4}, 0, 1},
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ans1184{1},
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},
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question1184{
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para1184{[]int{1, 2, 3, 4}, 0, 2},
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ans1184{3},
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},
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question1184{
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para1184{[]int{1, 2, 3, 4}, 0, 3},
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ans1184{4},
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},
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}
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fmt.Printf("------------------------Leetcode Problem 1184------------------------\n")
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for _, q := range qs {
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_, p := q.ans1184, q.para1184
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fmt.Printf("【input】:%v 【output】:%v\n", p, distanceBetweenBusStops(p.distance, p.start, p.destination))
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}
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fmt.Printf("\n\n\n")
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}
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59
Algorithms/1184. Distance Between Bus Stops/README.md
Executable file
59
Algorithms/1184. Distance Between Bus Stops/README.md
Executable file
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# [1184. Distance Between Bus Stops](https://leetcode.com/problems/distance-between-bus-stops/)
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## 题目:
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A bus has `n` stops numbered from `0` to `n - 1` that form a circle. We know the distance between all pairs of neighboring stops where `distance[i]` is the distance between the stops number `i` and `(i + 1) % n`.
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The bus goes along both directions i.e. clockwise and counterclockwise.
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Return the shortest distance between the given `start` and `destination` stops.
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**Example 1:**
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Input: distance = [1,2,3,4], start = 0, destination = 1
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Output: 1
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Explanation: Distance between 0 and 1 is 1 or 9, minimum is 1.
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**Example 2:**
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Input: distance = [1,2,3,4], start = 0, destination = 2
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Output: 3
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Explanation: Distance between 0 and 2 is 3 or 7, minimum is 3.
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**Example 3:**
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Input: distance = [1,2,3,4], start = 0, destination = 3
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Output: 4
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Explanation: Distance between 0 and 3 is 6 or 4, minimum is 4.
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**Constraints:**
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- `1 <= n <= 10^4`
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- `distance.length == n`
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- `0 <= start, destination < n`
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- `0 <= distance[i] <= 10^4`
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## 题目大意
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环形公交路线上有 n 个站,按次序从 0 到 n - 1 进行编号。我们已知每一对相邻公交站之间的距离,distance[i] 表示编号为 i 的车站和编号为 (i + 1) % n 的车站之间的距离。环线上的公交车都可以按顺时针和逆时针的方向行驶。返回乘客从出发点 start 到目的地 destination 之间的最短距离。
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提示:
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- 1 <= n <= 10^4
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- distance.length == n
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- 0 <= start, destination < n
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- 0 <= distance[i] <= 10^4
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## 解题思路
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- 给出一个数组,代表的是公交车站每站直接的距离。距离是按照数组下标的顺序给出的,公交车可以按照顺时针行驶,也可以按照逆时针行驶。问行驶的最短距离是多少。
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- 按照题意,分别算出顺时针和逆时针的行驶距离,比较两者距离,取出小值就是结果。
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