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添加 problem 25
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Algorithms/25.Reverse-Nodes-in-k-Group/README.md
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Algorithms/25.Reverse-Nodes-in-k-Group/README.md
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# [25. Reverse Nodes in k-Group](https://leetcode.com/problems/reverse-nodes-in-k-group/description/)
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## 题目
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Given a linked list, reverse the nodes of a linked list k at a time and return its modified list.
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k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is.
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Example:
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Given this linked list: 1->2->3->4->5
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For k = 2, you should return: 2->1->4->3->5
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For k = 3, you should return: 3->2->1->4->5
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Note:
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Only constant extra memory is allowed.
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You may not alter the values in the list's nodes, only nodes itself may be changed.
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## 题目大意
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这一题是 problem 24 的加强版,problem 24 是两两相邻的元素,翻转链表。而 problem 25 要求的是 k 个相邻的元素,翻转链表,problem 相当于是 k = 2 的特殊情况。
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package leetcode
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/**
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* Definition for singly-linked list.
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* type ListNode struct {
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* Val int
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* Next *ListNode
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* }
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*/
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func reverseKGroup(head *ListNode, k int) *ListNode {
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node := head
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for i := 0; i < k; i++ {
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if node == nil {
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return head
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}
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node = node.Next
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}
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newHead := reverse(head, node)
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head.Next = reverseKGroup(node, k)
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return newHead
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}
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func reverse(first *ListNode, last *ListNode) *ListNode {
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prev := last
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for first != last {
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tmp := first.Next
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first.Next = prev
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prev = first
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first = tmp
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}
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return prev
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}
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package leetcode
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import (
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"fmt"
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"testing"
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)
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type question25 struct {
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para25
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ans25
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}
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// para 是参数
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// one 代表第一个参数
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type para25 struct {
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one []int
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two int
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}
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// ans 是答案
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// one 代表第一个答案
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type ans25 struct {
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one []int
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}
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func Test_Problem25(t *testing.T) {
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qs := []question25{
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question25{
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para25{
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[]int{1, 2, 3, 4, 5},
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3,
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},
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ans25{[]int{3, 2, 1, 4, 5}},
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},
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question25{
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para25{
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[]int{1, 2, 3, 4, 5},
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1,
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},
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ans25{[]int{1, 2, 3, 4, 5}},
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},
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}
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fmt.Printf("------------------------Leetcode Problem 25------------------------\n")
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for _, q := range qs {
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_, p := q.ans25, q.para25
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fmt.Printf("【input】:%v 【output】:%v\n", p, L2s(reverseKGroup(S2l(p.one), p.two)))
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}
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fmt.Printf("\n\n\n")
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}
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