algorithm: find the middle of linked-list (#1096)

* Added Middle of linked-list implementation.

* Added Middle of LL function and tests

* Refactor: Added method in singly LL and its tests

* Refactor: Method name and inline test calls

* Use `!== null` instead of `!= null`

Co-authored-by: Lars Müller <34514239+appgurueu@users.noreply.github.com>
This commit is contained in:
Kartik Kapgate
2022-09-10 19:17:50 +05:30
committed by GitHub
parent 644d7f7faa
commit 6ad2467545
2 changed files with 37 additions and 1 deletions

View File

@ -6,7 +6,7 @@
* a singly linked list.
*/
// Methods - size, head, addLast, addFirst, addAt, removeFirst, removeLast, remove, removeAt, indexOf, isEmpty, elementAt, get, clean
// Methods - size, head, addLast, addFirst, addAt, removeFirst, removeLast, remove, removeAt, indexOf, isEmpty, elementAt, findMiddle, get, clean
class Node {
constructor (data) {
@ -193,6 +193,19 @@ class LinkedList {
return removedNode.data
}
// Returns a reference to middle node of linked list
findMiddle () {
// If there are two middle nodes, return the second middle node.
let fast = this.headNode
let slow = this.headNode
while (fast !== null && fast.next !== null) {
fast = fast.next.next
slow = slow.next
}
return slow
}
// make the linkedList Empty
clean () {
this.headNode = null

View File

@ -164,6 +164,29 @@ describe('SinglyLinkedList', () => {
expect(list.size()).toBe(1)
})
it('Middle node of linked list', () => {
const list = new LinkedList()
list.addFirst(1)
// Middle node for list having single node
expect(list.findMiddle().data).toEqual(1)
list.addLast(2)
list.addLast(3)
list.addLast(4)
list.addLast(5)
list.addLast(6)
list.addLast(7)
// Middle node for list having odd number of nodes
expect(list.findMiddle().data).toEqual(4)
list.addLast(10)
// Middle node for list having even number of nodes
expect(list.findMiddle().data).toEqual(5)
})
it('Check Iterator', () => {
const list = new LinkedList()