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Fixed Indendation Issues
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@ -3,36 +3,44 @@
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Find the largest palindrome made from the product of two 3-digit numbers.
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*/
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const largestPalindromic = (digits) => {
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let i, n, m, d, inf, sup, limit, number = 0;
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for (i = 1; i < digits; i++) {
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number = 10 * number + 9; //
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}
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inf = number; // highest (digits - 1) number, in this example highest 2 digit number
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sup = 10 * number + 9; // highest (digits) number, in this example highest 3 digit number
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let i
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let n
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let m
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let d
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let limit
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let number = 0
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function isPalindromic(n) {
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let p = 0, q = n, r;
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for (i = 1; i < digits; i++) {
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number = 10 * number + 9
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}
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const inf = number // highest (digits - 1) number, in this example highest 2 digit number
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const sup = 10 * number + 9 // highest (digits) number, in this example highest 3 digit number
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const isPalindromic = (n) => {
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let p = 0
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const q = n
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let r
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while (n > 0) {
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r = n % 10;
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p = 10 * p + r;
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n = Math.floor(n / 10);
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r = n % 10
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p = 10 * p + r
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n = Math.floor(n / 10)
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}
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return p === q; // returning whether the number is palindromic or not
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return p === q // returning whether the number is palindromic or not
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}
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for (n = sup * sup, m = inf * inf; n > m; n--) {
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if (isPalindromic(n)) {
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limit = Math.ceil(Math.sqrt(n));
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d = sup;
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limit = Math.ceil(Math.sqrt(n))
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d = sup
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while (d >= limit) {
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if (n % d === 0 && n / d > inf) {
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return n;
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return n
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}
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d -= 1;
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d -= 1
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}
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}
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}
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return NaN; // returning not a number, if any such case arise
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return NaN // returning not a number, if any such case arise
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}
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console.log(largestPalindromic(3));
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console.log(largestPalindromic(3))
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