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Explicitly cast result of Math.pow
to long
in Armstrong
(#4972)
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@ -27,7 +27,7 @@ public class Armstrong {
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while (originalNumber > 0) {
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long digit = originalNumber % 10;
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sum += Math.pow(digit, power); // The digit raised to the power of the number of digits and added to the sum.
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sum += (long) Math.pow(digit, power); // The digit raised to the power of the number of digits and added to the sum.
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originalNumber /= 10;
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}
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