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@ -1,53 +0,0 @@
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package com.thealgorithms.others;
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import java.util.Arrays;
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import java.util.Scanner;
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/**
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* To find triplet equals to given sum in complexity O(n*log(n))
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*
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* <p>
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* Array must be sorted
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*
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* @author Ujjawal Joshi
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* @date 2020.05.18
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* <p>
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* Test Cases: Input: 6 //Length of array 12 3 4 1 6 9 target=24 Output:3 9 12
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* Explanation: There is a triplet (12, 3 and 9) present in the array whose sum
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* is 24.
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*/
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class ThreeSum {
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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int n = sc.nextInt(); // Length of an array
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int[] a = new int[n];
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for (int i = 0; i < n; i++) {
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a[i] = sc.nextInt();
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}
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System.out.println("Target");
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int n_find = sc.nextInt();
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Arrays.sort(a); // Sort the array if array is not sorted
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for (int i = 0; i < n; i++) {
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int l = i + 1, r = n - 1;
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while (l < r) {
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if (a[i] + a[l] + a[r] == n_find) {
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System.out.println(a[i] + " " + a[l] + " " + a[r]);
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break;
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} // if you want all the triplets write l++;r--; insted of break;
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else if (a[i] + a[l] + a[r] < n_find) {
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l++;
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} else {
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r--;
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}
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}
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}
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sc.close();
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}
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}
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