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Add tests, remove main
in DiceThrow/DP.java
(#5644)
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@ -788,6 +788,7 @@
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* [ClimbStairsTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/ClimbStairsTest.java)
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* [CoinChangeTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/CoinChangeTest.java)
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* [CountFriendsPairingTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/CountFriendsPairingTest.java)
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* [DPTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/DPTest.java)
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* [EditDistanceTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/EditDistanceTest.java)
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* [EggDroppingTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/EggDroppingTest.java)
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* [KnapsackMemoizationTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/KnapsackMemoizationTest.java)
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@ -9,6 +9,7 @@ keep on counting the results that sum to X. This can be done using recursion. */
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/* Hence, storing the results of the solved sub-problems saves time.
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And it can be done using Dynamic Programming(DP).
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// Time Complexity: O(m * n * x) where m is number of faces, n is number of dice and x is given sum.
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Following is implementation of Dynamic Programming approach. */
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// Code ---->
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// Java program to find number of ways to get sum 'x' with 'n'
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@ -43,21 +44,4 @@ final class DP {
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return table[n][x];
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}
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public static void main(String[] args) {
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System.out.println(findWays(4, 2, 1));
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System.out.println(findWays(2, 2, 3));
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System.out.println(findWays(6, 3, 8));
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System.out.println(findWays(4, 2, 5));
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System.out.println(findWays(4, 3, 5));
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}
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}
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/*
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OUTPUT:
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0
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2
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21
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4
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6
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*/
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// Time Complexity: O(m * n * x) where m is number of faces, n is number of dice and x is given sum.
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@ -0,0 +1,56 @@
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package com.thealgorithms.dynamicprogramming;
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import static org.junit.jupiter.api.Assertions.assertEquals;
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import org.junit.jupiter.api.Test;
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public class DPTest {
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@Test
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void testSumLessThanMinimumFaceValue() {
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// When the sum is less than the minimum possible face value
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// There are 0 ways to achieve the sum
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assertEquals(0, DP.findWays(4, 2, 1)); // 4 faces, 2 dice, sum = 1
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}
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@Test
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void testTwoDiceWithSumEqualToTwo() {
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// When there are 2 dice and the sum is equal to the number of dice
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// The only way is to have both dice showing 1
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assertEquals(1, DP.findWays(2, 2, 2)); // 2 faces, 2 dice, sum = 2
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}
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@Test
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void testTwoDiceWithSumThree() {
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// When there are 2 dice and the sum is equal to 3
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// Possible combinations are (1,2) and (2,1)
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assertEquals(2, DP.findWays(2, 2, 3)); // 2 faces, 2 dice, sum = 3
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}
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@Test
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void testThreeDiceWithSumEight() {
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// Test for 3 dice, each having 6 faces
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// Possible combinations to make sum of 8
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assertEquals(21, DP.findWays(6, 3, 8)); // 6 faces, 3 dice, sum = 8
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}
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@Test
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void testTwoDiceWithSumFive() {
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// Test for 2 dice, with 4 faces to make sum of 5
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// Possible combinations: (1,4), (2,3), (3,2), (4,1)
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assertEquals(4, DP.findWays(4, 2, 5)); // 4 faces, 2 dice, sum = 5
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}
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@Test
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void testThreeDiceWithSumFive() {
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// Test for 3 dice, with 4 faces to make sum of 5
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// Possible combinations: (1,1,3), (1,2,2), (1,3,1), (2,1,2), (2,2,1), (3,1,1)
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assertEquals(6, DP.findWays(4, 3, 5)); // 4 faces, 3 dice, sum = 5
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}
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@Test
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void testEdgeCaseZeroSum() {
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// Test for 0 sum with 0 dice
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assertEquals(0, DP.findWays(4, 0, 0)); // 4 faces, 0 dice, sum = 0
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}
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}
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