Add tests, remove main in DiceThrow/DP.java (#5644)

This commit is contained in:
Hardik Pawar
2024-10-10 00:46:20 +05:30
committed by GitHub
parent 6ddb26f48d
commit 4a0e46dae6
3 changed files with 58 additions and 17 deletions

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@ -788,6 +788,7 @@
* [ClimbStairsTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/ClimbStairsTest.java)
* [CoinChangeTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/CoinChangeTest.java)
* [CountFriendsPairingTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/CountFriendsPairingTest.java)
* [DPTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/DPTest.java)
* [EditDistanceTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/EditDistanceTest.java)
* [EggDroppingTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/EggDroppingTest.java)
* [KnapsackMemoizationTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/dynamicprogramming/KnapsackMemoizationTest.java)

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@ -9,6 +9,7 @@ keep on counting the results that sum to X. This can be done using recursion. */
/* Hence, storing the results of the solved sub-problems saves time.
And it can be done using Dynamic Programming(DP).
// Time Complexity: O(m * n * x) where m is number of faces, n is number of dice and x is given sum.
Following is implementation of Dynamic Programming approach. */
// Code ---->
// Java program to find number of ways to get sum 'x' with 'n'
@ -43,21 +44,4 @@ final class DP {
return table[n][x];
}
public static void main(String[] args) {
System.out.println(findWays(4, 2, 1));
System.out.println(findWays(2, 2, 3));
System.out.println(findWays(6, 3, 8));
System.out.println(findWays(4, 2, 5));
System.out.println(findWays(4, 3, 5));
}
}
/*
OUTPUT:
0
2
21
4
6
*/
// Time Complexity: O(m * n * x) where m is number of faces, n is number of dice and x is given sum.

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@ -0,0 +1,56 @@
package com.thealgorithms.dynamicprogramming;
import static org.junit.jupiter.api.Assertions.assertEquals;
import org.junit.jupiter.api.Test;
public class DPTest {
@Test
void testSumLessThanMinimumFaceValue() {
// When the sum is less than the minimum possible face value
// There are 0 ways to achieve the sum
assertEquals(0, DP.findWays(4, 2, 1)); // 4 faces, 2 dice, sum = 1
}
@Test
void testTwoDiceWithSumEqualToTwo() {
// When there are 2 dice and the sum is equal to the number of dice
// The only way is to have both dice showing 1
assertEquals(1, DP.findWays(2, 2, 2)); // 2 faces, 2 dice, sum = 2
}
@Test
void testTwoDiceWithSumThree() {
// When there are 2 dice and the sum is equal to 3
// Possible combinations are (1,2) and (2,1)
assertEquals(2, DP.findWays(2, 2, 3)); // 2 faces, 2 dice, sum = 3
}
@Test
void testThreeDiceWithSumEight() {
// Test for 3 dice, each having 6 faces
// Possible combinations to make sum of 8
assertEquals(21, DP.findWays(6, 3, 8)); // 6 faces, 3 dice, sum = 8
}
@Test
void testTwoDiceWithSumFive() {
// Test for 2 dice, with 4 faces to make sum of 5
// Possible combinations: (1,4), (2,3), (3,2), (4,1)
assertEquals(4, DP.findWays(4, 2, 5)); // 4 faces, 2 dice, sum = 5
}
@Test
void testThreeDiceWithSumFive() {
// Test for 3 dice, with 4 faces to make sum of 5
// Possible combinations: (1,1,3), (1,2,2), (1,3,1), (2,1,2), (2,2,1), (3,1,1)
assertEquals(6, DP.findWays(4, 3, 5)); // 4 faces, 3 dice, sum = 5
}
@Test
void testEdgeCaseZeroSum() {
// Test for 0 sum with 0 dice
assertEquals(0, DP.findWays(4, 0, 0)); // 4 faces, 0 dice, sum = 0
}
}