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Enhance docs, add more tests in NumberAppearingOddTimes
(#5857)
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@ -1,21 +1,41 @@
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package com.thealgorithms.bitmanipulation;
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/**
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* Find the Number Appearing Odd Times in an array
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* This class provides a method to find the element that appears an
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* odd number of times in an array. All other elements in the array
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* must appear an even number of times for the logic to work.
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*
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* The solution uses the XOR operation, which has the following properties:
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* - a ^ a = 0 (XOR-ing the same numbers cancels them out)
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* - a ^ 0 = a
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* - XOR is commutative and associative.
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*
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* Time Complexity: O(n), where n is the size of the array.
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* Space Complexity: O(1), as no extra space is used.
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*
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* Usage Example:
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* int result = NumberAppearingOddTimes.findOddOccurrence(new int[]{1, 2, 1, 2, 3});
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* // result will be 3
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*
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* @author Lakshyajeet Singh Goyal (https://github.com/DarkMatter-999)
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*/
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public final class NumberAppearingOddTimes {
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private NumberAppearingOddTimes() {
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}
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/**
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* Finds the element in the array that appears an odd number of times.
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*
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* @param arr the input array containing integers, where all elements
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* except one appear an even number of times.
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* @return the integer that appears an odd number of times.
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*/
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public static int findOddOccurrence(int[] arr) {
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int result = 0;
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// XOR all elements in the array
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for (int num : arr) {
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result ^= num;
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}
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return result;
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}
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}
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@ -2,22 +2,48 @@ package com.thealgorithms.bitmanipulation;
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import static org.junit.jupiter.api.Assertions.assertEquals;
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import org.junit.jupiter.api.Test;
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import java.util.stream.Stream;
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import org.junit.jupiter.params.ParameterizedTest;
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import org.junit.jupiter.params.provider.Arguments;
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import org.junit.jupiter.params.provider.MethodSource;
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class NumberAppearingOddTimesTest {
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@Test
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void testFindOddOccurrence() {
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int[] arr1 = {5, 6, 7, 8};
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assertEquals(12, NumberAppearingOddTimes.findOddOccurrence(arr1));
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/**
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* Parameterized test for findOddOccurrence method. Tests multiple
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* input arrays and their expected results.
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*/
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@ParameterizedTest
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@MethodSource("provideTestCases")
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void testFindOddOccurrence(int[] input, int expected) {
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assertEquals(expected, NumberAppearingOddTimes.findOddOccurrence(input));
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}
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int[] arr2 = {2, 3, 5, 4, 5, 2, 4, 3, 5, 2, 4, 4, 2};
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assertEquals(5, NumberAppearingOddTimes.findOddOccurrence(arr2));
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/**
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* Provides test cases for the parameterized test.
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* Each test case consists of an input array and the expected result.
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*/
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private static Stream<Arguments> provideTestCases() {
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return Stream.of(
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// Single element appearing odd times (basic case)
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Arguments.of(new int[] {5, 6, 7, 8, 6, 7, 5}, 8),
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int[] arr3 = {10, 10, 20, 20, 30};
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assertEquals(30, NumberAppearingOddTimes.findOddOccurrence(arr3));
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// More complex case with multiple pairs
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Arguments.of(new int[] {2, 3, 5, 4, 5, 2, 4, 3, 5, 2, 4, 4, 2}, 5),
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int[] arr4 = {-5, -5, -3, -3, -7, -7, -7};
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assertEquals(-7, NumberAppearingOddTimes.findOddOccurrence(arr4));
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// Case with only one element appearing once
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Arguments.of(new int[] {10, 10, 20, 20, 30}, 30),
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// Negative numbers with an odd occurrence
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Arguments.of(new int[] {-5, -5, -3, -3, -7, -7, -7}, -7),
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// All elements cancel out to 0 (even occurrences of all elements)
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Arguments.of(new int[] {1, 2, 1, 2}, 0),
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// Array with a single element (trivial case)
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Arguments.of(new int[] {42}, 42),
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// Large array with repeated patterns
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Arguments.of(new int[] {1, 1, 2, 2, 3, 3, 3, 4, 4}, 3));
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}
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}
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