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Add SlidingWindowMaximum
algorithm (#5839)
This commit is contained in:
@ -207,6 +207,7 @@
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* [PriorityQueues](https://github.com/TheAlgorithms/Java/blob/master/src/main/java/com/thealgorithms/datastructures/queues/PriorityQueues.java)
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* [Queue](https://github.com/TheAlgorithms/Java/blob/master/src/main/java/com/thealgorithms/datastructures/queues/Queue.java)
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* [QueueByTwoStacks](https://github.com/TheAlgorithms/Java/blob/master/src/main/java/com/thealgorithms/datastructures/queues/QueueByTwoStacks.java)
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* [SlidingWindowMaximum](https://github.com/TheAlgorithms/Java/blob/master/src/main/java/com/thealgorithms/datastructures/queues/SlidingWindowMaximum.java)
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* [TokenBucket](https://github.com/TheAlgorithms/Java/blob/master/src/main/java/com/thealgorithms/datastructures/queues/TokenBucket.java)
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* stacks
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* [NodeStack](https://github.com/TheAlgorithms/Java/blob/master/src/main/java/com/thealgorithms/datastructures/stacks/NodeStack.java)
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@ -882,6 +883,7 @@
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* [PriorityQueuesTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/queues/PriorityQueuesTest.java)
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* [QueueByTwoStacksTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/queues/QueueByTwoStacksTest.java)
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* [QueueTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/queues/QueueTest.java)
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* [SlidingWindowMaximumTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/queues/SlidingWindowMaximumTest.java)
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* [TokenBucketTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/queues/TokenBucketTest.java)
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* stacks
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* [NodeStackTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/stacks/NodeStackTest.java)
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@ -0,0 +1,63 @@
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package com.thealgorithms.datastructures.queues;
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import java.util.Deque;
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import java.util.LinkedList;
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/**
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* The {@code SlidingWindowMaximum} class provides a method to efficiently compute
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* the maximum element within every sliding window of size {@code k} in a given array.
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*
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* <p>The algorithm uses a deque to maintain the indices of useful elements within
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* the current sliding window. The time complexity of this approach is O(n) since
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* each element is processed at most twice.
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*
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* @author Hardvan
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*/
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public final class SlidingWindowMaximum {
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private SlidingWindowMaximum() {
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}
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/**
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* Returns an array of the maximum values for each sliding window of size {@code k}.
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* <p>If {@code nums} has fewer elements than {@code k}, the result will be an empty array.
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* <p>Example:
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* <pre>
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* Input: nums = [1, 3, -1, -3, 5, 3, 6, 7], k = 3
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* Output: [3, 3, 5, 5, 6, 7]
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* </pre>
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*
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* @param nums the input array of integers
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* @param k the size of the sliding window
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* @return an array containing the maximum element for each sliding window
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*/
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public static int[] maxSlidingWindow(int[] nums, int k) {
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int n = nums.length;
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if (n < k || k == 0) {
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return new int[0];
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}
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int[] result = new int[n - k + 1];
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Deque<Integer> deque = new LinkedList<>();
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for (int i = 0; i < n; i++) {
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// Remove elements from the front of the deque if they are out of the current window
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if (!deque.isEmpty() && deque.peekFirst() < i - k + 1) {
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deque.pollFirst();
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}
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// Remove elements from the back if they are smaller than the current element
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while (!deque.isEmpty() && nums[deque.peekLast()] < nums[i]) {
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deque.pollLast();
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}
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// Add the current element's index to the deque
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deque.offerLast(i);
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// Store the maximum element for the current window (starting from the k-1th element)
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if (i >= k - 1) {
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result[i - k + 1] = nums[deque.peekFirst()];
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}
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}
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return result;
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}
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}
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@ -0,0 +1,50 @@
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package com.thealgorithms.datastructures.queues;
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import static org.junit.jupiter.api.Assertions.assertArrayEquals;
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import java.util.stream.Stream;
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import org.junit.jupiter.params.ParameterizedTest;
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import org.junit.jupiter.params.provider.Arguments;
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import org.junit.jupiter.params.provider.MethodSource;
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public class SlidingWindowMaximumTest {
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@ParameterizedTest
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@MethodSource("provideTestCases")
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public void testMaxSlidingWindow(int[] nums, int k, int[] expected) {
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assertArrayEquals(expected, SlidingWindowMaximum.maxSlidingWindow(nums, k));
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}
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private static Stream<Arguments> provideTestCases() {
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return Stream.of(
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// Test case 1: Example from the problem statement
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Arguments.of(new int[] {1, 3, -1, -3, 5, 3, 6, 7}, 3, new int[] {3, 3, 5, 5, 6, 7}),
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// Test case 2: All elements are the same
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Arguments.of(new int[] {4, 4, 4, 4, 4}, 2, new int[] {4, 4, 4, 4}),
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// Test case 3: Window size equals the array length
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Arguments.of(new int[] {2, 1, 5, 3, 6}, 5, new int[] {6}),
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// Test case 4: Single element array with window size 1
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Arguments.of(new int[] {7}, 1, new int[] {7}),
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// Test case 5: Window size larger than the array length
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Arguments.of(new int[] {1, 2, 3}, 4, new int[] {}),
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// Test case 6: Decreasing sequence
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Arguments.of(new int[] {9, 8, 7, 6, 5, 4}, 3, new int[] {9, 8, 7, 6}),
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// Test case 7: Increasing sequence
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Arguments.of(new int[] {1, 2, 3, 4, 5}, 2, new int[] {2, 3, 4, 5}),
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// Test case 8: k is zero
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Arguments.of(new int[] {1, 3, -1, -3, 5, 3, 6, 7}, 0, new int[] {}),
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// Test case 9: Array with negative numbers
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Arguments.of(new int[] {-4, -2, -5, -1, -3}, 3, new int[] {-2, -1, -1}),
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// Test case 10: Empty array
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Arguments.of(new int[] {}, 3, new int[] {}));
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}
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}
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