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path: simplify ResolveToLastNode
License: MIT Signed-off-by: Łukasz Magiera <magik6k@gmail.com>
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@ -70,7 +70,10 @@ func (r *Resolver) ResolveToLastNode(ctx context.Context, fpath path.Path) (ipld
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for len(p) > 0 {
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lnk, rest, err := r.ResolveOnce(ctx, r.DAG, nd, p)
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if lnk != nil {
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if lnk == nil {
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break
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}
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if err != nil {
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return nil, nil, err
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}
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@ -81,22 +84,27 @@ func (r *Resolver) ResolveToLastNode(ctx context.Context, fpath path.Path) (ipld
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}
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nd = next
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p = rest
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continue
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}
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if len(p) == 0 {
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return nd, nil, nil
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}
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// Confirm the path exists within the object
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val, rest, err := nd.Resolve(p)
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if err != nil {
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return nil, nil, err
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}
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if len(rest) > 0 {
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return nil, nil, errors.New("path failed to resolve fully")
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}
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switch val.(type) {
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case *ipld.Link:
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return nil, nil, errors.New("inconsistent ResolveOnce / nd.Resolve")
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default:
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return nd, p, nil
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}
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}
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return nd, nil, nil
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}
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// ResolvePath fetches the node for given path. It returns the last item
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