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resolve and pin in one step
instead of resolving all the pins first and then pinning, pin after resolving each pin. This: 1. Avoids storing all the nodes in memory. 2. Avoids not showing pin progress. fixes #4122 License: MIT Signed-off-by: Steven Allen <steven@stebalien.com>
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@ -22,18 +22,17 @@ import (
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uio "github.com/ipfs/go-ipfs/unixfs/io"
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cid "gx/ipfs/QmNp85zy9RLrQ5oQD4hPyS39ezrrXpcaa7R4Y9kxdWQLLQ/go-cid"
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node "gx/ipfs/QmPN7cwmpcc4DWXb4KTB9dNAJgjuPY69h3npsMfhRrQL9c/go-ipld-format"
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)
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func Pin(n *core.IpfsNode, ctx context.Context, paths []string, recursive bool) ([]*cid.Cid, error) {
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dagnodes := make([]node.Node, 0)
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out := make([]*cid.Cid, len(paths))
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r := &path.Resolver{
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DAG: n.DAG,
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ResolveOnce: uio.ResolveUnixfsOnce,
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}
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for _, fpath := range paths {
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for i, fpath := range paths {
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p, err := path.ParsePath(fpath)
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if err != nil {
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return nil, err
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@ -43,18 +42,11 @@ func Pin(n *core.IpfsNode, ctx context.Context, paths []string, recursive bool)
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if err != nil {
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return nil, fmt.Errorf("pin: %s", err)
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}
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dagnodes = append(dagnodes, dagnode)
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}
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var out []*cid.Cid
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for _, dagnode := range dagnodes {
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c := dagnode.Cid()
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err := n.Pinning.Pin(ctx, dagnode, recursive)
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err = n.Pinning.Pin(ctx, dagnode, recursive)
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if err != nil {
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return nil, fmt.Errorf("pin: %s", err)
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}
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out = append(out, c)
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out[i] = dagnode.Cid()
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}
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err := n.Pinning.Flush()
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