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review:【BPM 工作流】并行分支使用包容网关实现 =》补充一些注释说明
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@ -592,8 +592,9 @@ public class SimpleModelUtils {
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private static class ParallelBranchNodeConvert implements NodeConvert {
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private static class ParallelBranchNodeConvert implements NodeConvert {
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/**
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/**
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* 并行分支使用包容网关。需要设置所有出口条件表达式的值为 true.
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* 并行分支使用包容网关。需要设置所有出口条件表达式的值为 true 。原因是,解决 https://t.zsxq.com/m6GXh 反馈问题
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* 参见: {@link ConditionNodeConvert#buildSequenceFlow}
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*
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* @see {@link ConditionNodeConvert#buildSequenceFlow}
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*/
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*/
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@Override
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@Override
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public List<InclusiveGateway> convertList(BpmSimpleModelNodeVO node) {
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public List<InclusiveGateway> convertList(BpmSimpleModelNodeVO node) {
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@ -265,7 +265,7 @@ public class BpmProcessInstanceServiceImpl implements BpmProcessInstanceService
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// 3. 获取下一个将要执行的节点集合
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// 3. 获取下一个将要执行的节点集合
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FlowElement flowElement = bpmnModel.getFlowElement(task.getTaskDefinitionKey());
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FlowElement flowElement = bpmnModel.getFlowElement(task.getTaskDefinitionKey());
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List<FlowNode> nextFlowNodes = BpmnModelUtils.getNextFlowNodes(flowElement, bpmnModel, processVariables);
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List<FlowNode> nextFlowNodes = BpmnModelUtils.getNextFlowNodes(flowElement, bpmnModel, processVariables);
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// 仅仅获取 UserTask 节点 TODO:如果网关节点和网关节点相连,获取下个 UserTask. 貌似有点不准。
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// 仅仅获取 UserTask 节点 TODO add from jason:如果网关节点和网关节点相连,获取下个 UserTask. 貌似有点不准。
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List<FlowNode> nextUserTaskList = CollectionUtils.filterList(nextFlowNodes, node -> node instanceof UserTask);
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List<FlowNode> nextUserTaskList = CollectionUtils.filterList(nextFlowNodes, node -> node instanceof UserTask);
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List<ActivityNode> nextActivityNodes = convertList(nextUserTaskList, node -> new ActivityNode().setId(node.getId())
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List<ActivityNode> nextActivityNodes = convertList(nextUserTaskList, node -> new ActivityNode().setId(node.getId())
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.setName(node.getName()).setNodeType(BpmSimpleModelNodeTypeEnum.APPROVE_NODE.getType())
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.setName(node.getName()).setNodeType(BpmSimpleModelNodeTypeEnum.APPROVE_NODE.getType())
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