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f0f9e75a82
When running testcase gdb.opt/inline-locals.exp on openSUSE Tumbleweed, I get:
...
(gdb) info locals^M
array = {0 <repeats 48 times>, 15775231, 0, 194, 0, -11497, 32767, 4199061, \
0, 0, 0, 0, 0, 4198992, 0, 4198432, 0}^M
(gdb) FAIL: gdb.opt/inline-locals.exp: info locals above bar 2
...
Fix this by:
- completely initializing array before printing any value
- updating the pattern to match "array = {0 <repeats 64 times>}"
Tested on x86_64-linux.
gdb/testsuite/ChangeLog:
2020-07-21 Tom de Vries <tdevries@suse.de>
* gdb.opt/inline-locals.c (init_array): New func.
(func1): Use init_array.
* gdb.opt/inline-locals.exp: Update pattern.
72 lines
1.5 KiB
C
72 lines
1.5 KiB
C
/* Copyright (C) 2008-2020 Free Software Foundation, Inc.
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This program is free software; you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation; either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with this program. If not, see <http://www.gnu.org/licenses/>. */
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/* This is only ever run if it is compiled with a new-enough GCC, but
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we don't want the compilation to fail if compiled by some other
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compiler. */
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#ifdef __GNUC__
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#define ATTR __attribute__((always_inline))
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#else
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#define ATTR
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#endif
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int x, y;
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volatile int z = 0;
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volatile int result;
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volatile int *array_p;
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void bar(void);
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void
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init_array (int *array, int n)
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{
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int i;
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for (i = 0; i < n; ++i)
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array[i] = 0;
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}
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inline ATTR int func1(int arg1)
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{
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int array[64];
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init_array (array, 64);
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array_p = array;
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array[0] = result;
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array[1] = arg1;
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bar ();
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return x * y + array_p[0] * arg1;
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}
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inline ATTR int func2(int arg2)
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{
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return x * func1 (arg2);
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}
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int main (void)
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{
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int val;
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x = 7;
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y = 8;
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bar ();
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val = func1 (result);
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result = val;
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val = func2 (result);
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result = val;
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return 0;
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}
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