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Make copy_name return std::string
This changes copy_name to return a std::string, updating all the callers. In some cases, an extra copy was removed. This also required a little bit of constification. Tested by the buildbot. gdb/ChangeLog 2019-04-19 Tom Tromey <tom@tromey.com> * type-stack.h (struct type_stack) <insert>: Constify string. * type-stack.c (type_stack::insert): Constify string. * gdbtypes.h (lookup_template_type): Update. (address_space_name_to_int): Update. * gdbtypes.c (address_space_name_to_int): Make space_identifier const. (lookup_template_type): Make name const. * c-exp.y: Update rules. (lex_one_token, classify_name, classify_inner_name) (c_print_token): Update. * p-exp.y: Update rules. (yylex): Update. * f-exp.y: Update rules. (yylex): Update. * d-exp.y: Update rules. (lex_one_token, classify_name, classify_inner_name): Update. * parse.c (write_dollar_variable, copy_name): Return std::string. * parser-defs.h (copy_name): Change return type. * m2-exp.y: Update rules. (yylex): Update. * go-exp.y (lex_one_token): Update. Update rules. (classify_unsafe_function, classify_packaged_name) (classify_name, yylex): Update.
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@ -160,7 +160,7 @@ public:
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tp_pointer, and the new values are inserted above the first
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item. */
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void insert (struct expr_builder *pstate, char *string);
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void insert (struct expr_builder *pstate, const char *string);
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/* Append the elements of the type stack FROM to the type stack
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THIS. Always returns THIS. */
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