From 5c3a57ea1c147502a769312374853955bbdd4dca Mon Sep 17 00:00:00 2001
From: c0dedance <38075730+c0dedance@users.noreply.github.com>
Date: Tue, 25 Oct 2022 21:34:47 +0800
Subject: [PATCH] =?UTF-8?q?Update=200343.=E6=95=B4=E6=95=B0=E6=8B=86?=
 =?UTF-8?q?=E5=88=86.md?=
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内层for循环优化
---
 problems/0343.整数拆分.md | 12 ++++++------
 1 file changed, 6 insertions(+), 6 deletions(-)

diff --git a/problems/0343.整数拆分.md b/problems/0343.整数拆分.md
index 00e6a9da..f6683954 100644
--- a/problems/0343.整数拆分.md
+++ b/problems/0343.整数拆分.md
@@ -89,7 +89,7 @@ dp[i] 是依靠 dp[i - j]的状态，所以遍历i一定是从前向后遍历，
 所以遍历顺序为：
 ```
 for (int i = 3; i <= n ; i++) {
-    for (int j = 1; j < i - 1; j++) {
+    for (int j = 1; j <= i / 2; j++) {
         dp[i] = max(dp[i], max((i - j) * j, dp[i - j] * j));
     }
 }
@@ -110,7 +110,7 @@ public:
         vector<int> dp(n + 1);
         dp[2] = 1;
         for (int i = 3; i <= n ; i++) {
-            for (int j = 1; j < i - 1; j++) {
+            for (int j = 1; j <= i / 2; j++) {
                 dp[i] = max(dp[i], max((i - j) * j, dp[i - j] * j));
             }
         }
@@ -167,7 +167,7 @@ public:
         dp[2] = 2;
         dp[3] = 3;
         for (int i = 4; i <= n ; i++) {
-            for (int j = 1; j < i - 1; j++) {
+            for (int j = 1; j <= i / 2; j++) {
                 dp[i] = max(dp[i], dp[i - j] * dp[j]);
             }
         }
@@ -224,7 +224,7 @@ class Solution:
             # 假设对正整数 i 拆分出的第一个正整数是 j（1 <= j < i），则有以下两种方案：
             # 1) 将 i 拆分成 j 和 i−j 的和，且 i−j 不再拆分成多个正整数，此时的乘积是 j * (i-j)
             # 2) 将 i 拆分成 j 和 i−j 的和，且 i−j 继续拆分成多个正整数，此时的乘积是 j * dp[i-j]
-            for j in range(1, i - 1):
+            for j in range(1, i / 2 + 1):
                 dp[i] = max(dp[i], max(j * (i - j), j * dp[i - j]))
         return dp[n]
 ```
@@ -281,7 +281,7 @@ var integerBreak = function(n) {
     dp[2] = 1
 
     for(let i = 3; i <= n; i++) {
-        for(let j = 1; j < i; j++) {
+        for(let j = 1; j <= i / 2; j++) {
             dp[i] = Math.max(dp[i], dp[i - j] * j, (i - j) * j)
         }
     }
@@ -306,7 +306,7 @@ function integerBreak(n: number): number {
     const dp: number[] = new Array(n + 1).fill(0);
     dp[2] = 1;
     for (let i = 3; i <= n; i++) {
-        for (let j = 1; j <= i - 2; j++) {
+        for (let j = 1; j <= i / 2; j++) {
             dp[i] = Math.max(dp[i], j * dp[i - j], j * (i - j));
         }
     }