From 1e81ef27100c8fc76bc38ec0135a4b18554398af Mon Sep 17 00:00:00 2001
From: Beim <73528776+162-jld@users.noreply.github.com>
Date: Sun, 1 May 2022 11:51:11 +0800
Subject: [PATCH 1/3] =?UTF-8?q?Update=200383.=E8=B5=8E=E9=87=91=E4=BF=A1.m?=
 =?UTF-8?q?d?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

---
 problems/0383.赎金信.md | 28 +++++++++++++++-------------
 1 file changed, 15 insertions(+), 13 deletions(-)

diff --git a/problems/0383.赎金信.md b/problems/0383.赎金信.md
index 00707347..56dcb8dd 100644
--- a/problems/0383.赎金信.md
+++ b/problems/0383.赎金信.md
@@ -110,23 +110,25 @@ Java：
 ```Java
 class Solution {
     public boolean canConstruct(String ransomNote, String magazine) {
-        //记录杂志字符串出现的次数
-        int[] arr = new int[26];
-        int temp;
-        for (int i = 0; i < magazine.length(); i++) {
-            temp = magazine.charAt(i) - 'a';
-            arr[temp]++;
+        // 定义一个哈希映射数组
+        int[] record = new int[26];
+
+        // 遍历
+        for(char c : magazine.toCharArray()){
+            record[c - 'a'] += 1;
         }
-        for (int i = 0; i < ransomNote.length(); i++) {
-            temp = ransomNote.charAt(i) - 'a';
-            //对于金信中的每一个字符都在数组中查找
-            //找到相应位减一，否则找不到返回false
-            if (arr[temp] > 0) {
-                arr[temp]--;
-            } else {
+
+        for(char c : ransomNote.toCharArray()){
+            record[c - 'a'] -= 1;
+        }
+        
+        // 如果数组中存在负数，说明ransomNote字符串总存在magazine中没有的字符
+        for(int i : record){
+            if(i < 0){
                 return false;
             }
         }
+
         return true;
     }
 }

From 8c596b161a140a76ea57130ac61a009308bd277c Mon Sep 17 00:00:00 2001
From: Beim <1497359184@qq.com>
Date: Sun, 1 May 2022 15:45:58 +0800
Subject: [PATCH 2/3] modify_problems_0383

---
 README.md | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/README.md b/README.md
index 1d7f219d..3d44ca69 100644
--- a/README.md
+++ b/README.md
@@ -31,7 +31,7 @@
 </p>
 
 
-# LeetCode 刷题攻略
+# LeetCode 刷题攻略1111
 
 ## 刷题攻略的背景
 
@@ -254,7 +254,7 @@
 33. [二叉树：构造一棵搜索树](./problems/0108.将有序数组转换为二叉搜索树.md)
 34. [二叉树：搜索树转成累加树](./problems/0538.把二叉搜索树转换为累加树.md)
 35. [二叉树：总结篇！（需要掌握的二叉树技能都在这里了）](./problems/二叉树总结篇.md)
- 
+
 ## 回溯算法 
 
 题目分类大纲如下：             

From 83c2fd2454bbbbeda82725d2c38a2b577d7434c6 Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?=E7=A8=8B=E5=BA=8F=E5=91=98Carl?= <sunxiuyang04@gmail.com>
Date: Wed, 18 May 2022 09:27:56 +0800
Subject: [PATCH 3/3] Update README.md

---
 README.md | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/README.md b/README.md
index 3d44ca69..01cab0b0 100644
--- a/README.md
+++ b/README.md
@@ -31,7 +31,7 @@
 </p>
 
 
-# LeetCode 刷题攻略1111
+# LeetCode 刷题攻略
 
 ## 刷题攻略的背景