From f77fa05df7f506b33be4efa4eaca07beabc2e725 Mon Sep 17 00:00:00 2001
From: Yuhao Ju <juguaguaji@gmail.com>
Date: Sat, 17 Dec 2022 16:26:04 +0800
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---
 ...14.买卖股票的最佳时机含手续费.md | 16 ++++++++--------
 1 file changed, 8 insertions(+), 8 deletions(-)

diff --git a/problems/0714.买卖股票的最佳时机含手续费.md b/problems/0714.买卖股票的最佳时机含手续费.md
index faa56d42..005f9c38 100644
--- a/problems/0714.买卖股票的最佳时机含手续费.md
+++ b/problems/0714.买卖股票的最佳时机含手续费.md
@@ -217,25 +217,25 @@ class Solution: # 贪心思路
 ```
 
 ### Go
-```golang
+```go
 func maxProfit(prices []int, fee int) int {
     var minBuy int = prices[0] //第一天买入
     var res int
-    for i:=0;i<len(prices);i++{
+    for i := 0; i < len(prices); i++ {
         //如果当前价格小于最低价，则在此处买入
-        if prices[i]<minBuy{
-            minBuy=prices[i]
+        if prices[i] < minBuy {
+            minBuy = prices[i]
         }
         //如果以当前价格卖出亏本，则不卖，继续找下一个可卖点
-        if prices[i]>=minBuy&&prices[i]-fee-minBuy<=0{
+        if prices[i] >= minBuy && prices[i]-fee-minBuy <= 0 {
             continue
         }
         //可以售卖了
-        if prices[i]>minBuy+fee{
+        if prices[i] > minBuy+fee {
             //累加每天的收益
-            res+=prices[i]-minBuy-fee
+            res += prices[i]-minBuy-fee
             //更新最小值（如果还在收获利润的区间里，表示并不是真正的卖出，而计算利润每次都要减去手续费，所以要让minBuy = prices[i] - fee;，这样在明天收获利润的时候，才不会多减一次手续费！）
-            minBuy=prices[i]-fee
+            minBuy = prices[i]-fee
         }
     }
     return res