diff --git a/problems/0209.长度最小的子数组.md b/problems/0209.长度最小的子数组.md
index d31cba3f..fbef7692 100644
--- a/problems/0209.长度最小的子数组.md
+++ b/problems/0209.长度最小的子数组.md
@@ -400,6 +400,54 @@ class Solution {
     }
 }
 ```
+Scala:
+
+滑动窗口:
+```scala
+object Solution {
+  def minSubArrayLen(target: Int, nums: Array[Int]): Int = {
+    var result = Int.MaxValue // 返回结果，默认最大值
+    var left = 0 // 慢指针，当sum>=target，向右移动
+    var sum = 0 // 窗口值的总和
+    for (right <- 0 until nums.length) {
+      sum += nums(right)
+      while (sum >= target) {
+        result = math.min(result, right - left + 1) // 产生新结果
+        sum -= nums(left) // 左指针移动，窗口总和减去左指针的值
+        left += 1 // 左指针向右移动
+      }
+    }
+    // 相当于三元运算符，return关键字可以省略
+    if (result == Int.MaxValue) 0 else result
+  }
+}
+```
+
+暴力解法:
+```scala
+object Solution {
+  def minSubArrayLen(target: Int, nums: Array[Int]): Int = {
+    import scala.util.control.Breaks
+    var res = Int.MaxValue
+    var subLength = 0
+    for (i <- 0 until nums.length) {
+      var sum = 0
+      Breaks.breakable(
+        for (j <- i until nums.length) {
+          sum += nums(j)
+          if (sum >= target) {
+            subLength = j - i + 1
+            res = math.min(subLength, res)
+            Breaks.break()
+          }
+        }
+      )
+    }
+    // 相当于三元运算符
+    if (res == Int.MaxValue) 0 else res
+  }
+}
+```
 
 -----------------------
 <div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>
diff --git a/problems/0977.有序数组的平方.md b/problems/0977.有序数组的平方.md
index 24276bcf..0e79a3d6 100644
--- a/problems/0977.有序数组的平方.md
+++ b/problems/0977.有序数组的平方.md
@@ -358,7 +358,41 @@ class Solution {
     }
 }
 ```
+Scala:
 
+双指针:
+```scala
+object Solution {
+  def sortedSquares(nums: Array[Int]): Array[Int] = {
+    val res: Array[Int] = new Array[Int](nums.length)
+    var top = nums.length - 1
+    var i = 0
+    var j = nums.length - 1
+    while (i <= j) {
+      if (nums(i) * nums(i) <= nums(j) * nums(j)) {
+        // 当左侧平方小于等于右侧，res数组顶部放右侧的平方，并且top下移，j左移
+        res(top) = nums(j) * nums(j)
+        top -= 1
+        j -= 1
+      } else {
+        // 当左侧平方大于右侧，res数组顶部放左侧的平方，并且top下移，i右移
+        res(top) = nums(i) * nums(i)
+        top -= 1
+        i += 1
+      }
+    }
+    res
+  }
+}
+```
+骚操作(暴力思路):
+```scala
+object Solution {
+  def sortedSquares(nums: Array[Int]): Array[Int] = {
+    nums.map(x=>{x*x}).sortWith(_ < _)
+  }
+}
+```
 
 
 -----------------------