From f0ac0b2efd588164b74632e75a6c4358e2357781 Mon Sep 17 00:00:00 2001
From: fwqaaq <fwqaaq@gmail.com>
Date: Sun, 23 Jul 2023 18:57:41 +0800
Subject: [PATCH] =?UTF-8?q?Update=200115.=E4=B8=8D=E5=90=8C=E7=9A=84?=
 =?UTF-8?q?=E5=AD=90=E5=BA=8F=E5=88=97.md=20about=20rust?=
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---
 problems/0115.不同的子序列.md | 24 ++++++++++++++++++++++++
 1 file changed, 24 insertions(+)

diff --git a/problems/0115.不同的子序列.md b/problems/0115.不同的子序列.md
index 8c82880d..56516132 100644
--- a/problems/0115.不同的子序列.md
+++ b/problems/0115.不同的子序列.md
@@ -311,7 +311,31 @@ function numDistinct(s: string, t: string): number {
 };
 ```
 
+Rust:
 
+```rust
+impl Solution {
+    pub fn num_distinct(s: String, t: String) -> i32 {
+        if s.len() < t.len() {
+            return 0;
+        }
+        let mut dp = vec![vec![0; s.len() + 1]; t.len() + 1];
+        // i = 0, t 为空字符串，s 作为子序列的个数为 1（删除 s 所有元素）
+        dp[0] = vec![1; s.len() + 1];
+        for (i, char_t) in t.chars().enumerate() {
+            for (j, char_s) in s.chars().enumerate() {
+                if char_t == char_s {
+                    // t 的前 i 个字符在 s 的前 j 个字符中作为子序列的个数
+                    dp[i + 1][j + 1] = dp[i][j] + dp[i + 1][j];
+                    continue;
+                }
+                dp[i + 1][j + 1] = dp[i + 1][j];
+            }
+        }
+        dp[t.len()][s.len()]
+    }
+}
+```
 
 
 <p align="center">