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fix(0135): 加了注释,比原先少一次遍历
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@ -132,30 +132,33 @@ public:
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Java:
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Java:
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```java
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```java
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class Solution {
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class Solution {
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/**
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分两个阶段
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1、起点下标1 从左往右,只要 右边 比 左边 大,右边的糖果=左边 + 1
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2、起点下标 ratings.length - 2 从右往左, 只要左边 比 右边 大,此时 左边的糖果应该 取本身的糖果数(符合比它左边大) 和 右边糖果数 + 1 二者的最大值,这样才符合 它比它左边的大,也比它右边大
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*/
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public int candy(int[] ratings) {
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public int candy(int[] ratings) {
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int[] candy = new int[ratings.length];
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int[] candyVec = new int[ratings.length];
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for (int i = 0; i < candy.length; i++) {
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candyVec[0] = 1;
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candy[i] = 1;
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}
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for (int i = 1; i < ratings.length; i++) {
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for (int i = 1; i < ratings.length; i++) {
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if (ratings[i] > ratings[i - 1]) {
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if (ratings[i] > ratings[i - 1]) {
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candy[i] = candy[i - 1] + 1;
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candyVec[i] = candyVec[i - 1] + 1;
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} else {
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candyVec[i] = 1;
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}
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}
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}
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}
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for (int i = ratings.length - 2; i >= 0; i--) {
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for (int i = ratings.length - 2; i >= 0; i--) {
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if (ratings[i] > ratings[i + 1]) {
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if (ratings[i] > ratings[i + 1]) {
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candy[i] = Math.max(candy[i],candy[i + 1] + 1);
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candyVec[i] = Math.max(candyVec[i], candyVec[i + 1] + 1);
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}
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}
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}
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}
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int count = 0;
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int ans = 0;
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for (int i = 0; i < candy.length; i++) {
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for (int s : candyVec) {
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count += candy[i];
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ans += s;
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}
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}
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return ans;
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return count;
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}
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}
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}
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}
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```
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```
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