From e93f00aef737dad56bf4656a02c17cb66e214fcc Mon Sep 17 00:00:00 2001
From: ForsakenDelusion <144082461+ForsakenDelusion@users.noreply.github.com>
Date: Sat, 21 Dec 2024 18:06:53 +0800
Subject: [PATCH] =?UTF-8?q?0235.=E4=BA=8C=E5=8F=89=E6=90=9C=E7=B4=A2?=
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---
 problems/0235.二叉搜索树的最近公共祖先.md | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/problems/0235.二叉搜索树的最近公共祖先.md b/problems/0235.二叉搜索树的最近公共祖先.md
index 192bb031..3911261a 100644
--- a/problems/0235.二叉搜索树的最近公共祖先.md
+++ b/problems/0235.二叉搜索树的最近公共祖先.md
@@ -99,7 +99,7 @@ if (cur == NULL) return cur;
 
 * 确定单层递归的逻辑
 
-在遍历二叉搜索树的时候就是寻找区间[p->val, q->val]（注意这里是左闭又闭）
+在遍历二叉搜索树的时候就是寻找区间[p->val, q->val]（注意这里是左闭右闭）
 
 那么如果 cur->val 大于 p->val，同时 cur->val 大于q->val，那么就应该向左遍历（说明目标区间在左子树上）。