新增 0309.最佳买卖股票时机含冷冻期.md Go解法

This commit is contained in:
Wen
2021-11-06 20:29:00 +08:00
parent bc77968c31
commit e1e3b38eef

View File

@ -208,6 +208,40 @@ class Solution:
``` ```
Go Go
```go
// 最佳买卖股票时机含冷冻期 动态规划
// 时间复杂度O(n) 空间复杂度O(n)
func maxProfit(prices []int) int {
n := len(prices)
if n < 2 {
return 0
}
dp := make([][]int, n)
status := make([]int, n * 4)
for i := range dp {
dp[i] = status[:4]
status = status[4:]
}
dp[0][0] = -prices[0]
for i := 1; i < n; i++ {
dp[i][0] = max(dp[i - 1][0], max(dp[i - 1][1] - prices[i], dp[i - 1][3] - prices[i]))
dp[i][1] = max(dp[i - 1][1], dp[i - 1][3])
dp[i][2] = dp[i - 1][0] + prices[i]
dp[i][3] = dp[i - 1][2]
}
return max(dp[n - 1][1], max(dp[n - 1][2], dp[n - 1][3]))
}
func max(a, b int) int {
if a > b {
return a
}
return b
}
```
Javascript: Javascript: