From de34170f5cc1526eb0c4b1860943a57e6f41c4e1 Mon Sep 17 00:00:00 2001 From: ZongqinWang <1722249371@qq.com> Date: Fri, 27 May 2022 16:37:53 +0800 Subject: [PATCH] =?UTF-8?q?=E6=B7=BB=E5=8A=A0=200617.=E5=90=88=E5=B9=B6?= =?UTF-8?q?=E4=BA=8C=E5=8F=89=E6=A0=91.md=20Scala=E7=89=88=E6=9C=AC?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- problems/0617.合并二叉树.md | 53 ++++++++++++++++++++++++++++++++ 1 file changed, 53 insertions(+) diff --git a/problems/0617.合并二叉树.md b/problems/0617.合并二叉树.md index 55786ea9..d8bdc91c 100644 --- a/problems/0617.合并二叉树.md +++ b/problems/0617.合并二叉树.md @@ -631,7 +631,60 @@ function mergeTrees(root1: TreeNode | null, root2: TreeNode | null): TreeNode | }; ``` +## Scala +递归: +```scala +object Solution { + def mergeTrees(root1: TreeNode, root2: TreeNode): TreeNode = { + if (root1 == null) return root2 // 如果root1为空,返回root2 + if (root2 == null) return root1 // 如果root2为空,返回root1 + // 新建一个节点,值为两个节点的和 + var node = new TreeNode(root1.value + root2.value) + // 往下递归 + node.left = mergeTrees(root1.left, root2.left) + node.right = mergeTrees(root1.right, root2.right) + node // 返回node,return关键字可以省略 + } +} +``` + +迭代: +```scala +object Solution { + import scala.collection.mutable + def mergeTrees(root1: TreeNode, root2: TreeNode): TreeNode = { + if (root1 == null) return root2 + if (root2 == null) return root1 + var stack = mutable.Stack[TreeNode]() + // 先放node2再放node1 + stack.push(root2) + stack.push(root1) + while (!stack.isEmpty) { + var node1 = stack.pop() + var node2 = stack.pop() + node1.value += node2.value + if (node1.right != null && node2.right != null) { + stack.push(node2.right) + stack.push(node1.right) + } else { + if(node1.right == null){ + node1.right = node2.right + } + } + if (node1.left != null && node2.left != null) { + stack.push(node2.left) + stack.push(node1.left) + } else { + if(node1.left == null){ + node1.left = node2.left + } + } + } + root1 + } +} +``` -----------------------