Merge pull request #1741 from Jack-Zhang-1314/patch-10

update 0102.二叉树的层序遍历.md about using vecdeque rust
This commit is contained in:
程序员Carl
2022-11-23 10:06:20 +08:00
committed by GitHub

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@ -380,29 +380,32 @@ object Solution {
Rust:
```rust
pub fn level_order(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<Vec<i32>> {
let mut ans = Vec::new();
let mut stack = Vec::new();
if root.is_none(){
return ans;
use std::cell::RefCell;
use std::rc::Rc;
use std::collections::VecDeque;
impl Solution {
pub fn level_order(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<Vec<i32>> {
let mut res = vec![];
let mut queue = VecDeque::new();
if root.is_some() {
queue.push_back(root);
}
stack.push(root.unwrap());
while stack.is_empty()!= true{
let num = stack.len();
let mut level = Vec::new();
for _i in 0..num{
let tmp = stack.remove(0);
level.push(tmp.borrow_mut().val);
if tmp.borrow_mut().left.is_some(){
stack.push(tmp.borrow_mut().left.take().unwrap());
while !queue.is_empty() {
let mut temp = vec![];
for _ in 0..queue.len() {
let node = queue.pop_front().unwrap().unwrap();
temp.push(node.borrow().val);
if node.borrow().left.is_some() {
queue.push_back(node.borrow().left.clone());
}
if tmp.borrow_mut().right.is_some(){
stack.push(tmp.borrow_mut().right.take().unwrap());
if node.borrow().right.is_some() {
queue.push_back(node.borrow().right.clone());
}
}
ans.push(level);
res.push(temp);
}
res
}
ans
}
```
@ -665,29 +668,32 @@ object Solution {
Rust:
```rust
pub fn level_order(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<Vec<i32>> {
let mut ans = Vec::new();
let mut stack = Vec::new();
if root.is_none(){
return ans;
use std::cell::RefCell;
use std::collections::VecDeque;
use std::rc::Rc;
impl Solution {
pub fn level_order_bottom(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<Vec<i32>> {
let mut res = vec![];
let mut queue = VecDeque::new();
if root.is_some() {
queue.push_back(root);
}
stack.push(root.unwrap());
while stack.is_empty()!= true{
let num = stack.len();
let mut level = Vec::new();
for _i in 0..num{
let tmp = stack.remove(0);
level.push(tmp.borrow_mut().val);
if tmp.borrow_mut().left.is_some(){
stack.push(tmp.borrow_mut().left.take().unwrap());
while !queue.is_empty() {
let mut temp = vec![];
for _ in 0..queue.len() {
let node = queue.pop_front().unwrap().unwrap();
temp.push(node.borrow().val);
if node.borrow().left.is_some() {
queue.push_back(node.borrow().left.clone());
}
if tmp.borrow_mut().right.is_some(){
stack.push(tmp.borrow_mut().right.take().unwrap());
if node.borrow().right.is_some() {
queue.push_back(node.borrow().right.clone());
}
}
ans.push(level);
res.push(temp);
}
res.into_iter().rev().collect()
}
ans
}
```
@ -935,6 +941,39 @@ object Solution {
}
```
rust:
```rust
use std::cell::RefCell;
use std::collections::VecDeque;
use std::rc::Rc;
impl Solution {
pub fn right_side_view(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<i32> {
let mut res = vec![];
let mut queue = VecDeque::new();
if root.is_some() {
queue.push_back(root);
}
while !queue.is_empty() {
let len = queue.len();
for i in 0..len {
let node = queue.pop_front().unwrap().unwrap();
if i == len - 1 {
res.push(node.borrow().val);
}
if node.borrow().left.is_some() {
queue.push_back(node.borrow().left.clone());
}
if node.borrow().right.is_some() {
queue.push_back(node.borrow().right.clone());
}
}
}
res
}
}
```
# 637.二叉树的层平均值
[力扣题目链接](https://leetcode.cn/problems/average-of-levels-in-binary-tree/)
@ -1185,6 +1224,39 @@ object Solution {
}
```
rust:
```rust
use std::cell::RefCell;
use std::collections::VecDeque;
use std::rc::Rc;
impl Solution {
pub fn average_of_levels(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<f64> {
let mut res = vec![];
let mut queue = VecDeque::new();
if root.is_some() {
queue.push_back(root);
}
while !queue.is_empty() {
let len = queue.len();
let mut sum = 0;
for _ in 0..len {
let node = queue.pop_front().unwrap().unwrap();
sum += node.borrow().val;
if node.borrow().left.is_some() {
queue.push_back(node.borrow().left.clone());
}
if node.borrow().right.is_some() {
queue.push_back(node.borrow().right.clone());
}
}
res.push((sum as f64) / len as f64);
}
res
}
}
```
# 429.N叉树的层序遍历
[力扣题目链接](https://leetcode.cn/problems/n-ary-tree-level-order-traversal/)
@ -1456,6 +1528,54 @@ object Solution {
}
```
rust:
```rust
pub struct Solution;
#[derive(Debug, PartialEq, Eq)]
pub struct Node {
pub val: i32,
pub children: Vec<Option<Rc<RefCell<Node>>>>,
}
impl Node {
#[inline]
pub fn new(val: i32) -> Node {
Node {
val,
children: vec![],
}
}
}
use std::cell::RefCell;
use std::collections::VecDeque;
use std::rc::Rc;
impl Solution {
pub fn level_order(root: Option<Rc<RefCell<Node>>>) -> Vec<Vec<i32>> {
let mut res = vec![];
let mut queue = VecDeque::new();
if root.is_some() {
queue.push_back(root);
}
while !queue.is_empty() {
let mut temp = vec![];
for _ in 0..queue.len() {
let node = queue.pop_front().unwrap().unwrap();
temp.push(node.borrow().val);
if !node.borrow().children.is_empty() {
for n in node.borrow().children.clone() {
queue.push_back(n);
}
}
}
res.push(temp)
}
res
}
}
```
# 515.在每个树行中找最大值
[力扣题目链接](https://leetcode.cn/problems/find-largest-value-in-each-tree-row/)
@ -1686,6 +1806,38 @@ object Solution {
}
```
rust:
```rust
use std::cell::RefCell;
use std::collections::VecDeque;
use std::rc::Rc;
impl Solution {
pub fn largest_values(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<i32> {
let mut res = vec![];
let mut queue = VecDeque::new();
if root.is_some() {
queue.push_back(root);
}
while !queue.is_empty() {
let mut max = i32::MIN;
for _ in 0..queue.len() {
let node = queue.pop_front().unwrap().unwrap();
max = max.max(node.borrow().val);
if node.borrow().left.is_some() {
queue.push_back(node.borrow().left.clone());
}
if node.borrow().right.is_some() {
queue.push_back(node.borrow().right.clone());
}
}
res.push(max);
}
res
}
}
```
# 116.填充每个节点的下一个右侧节点指针
[力扣题目链接](https://leetcode.cn/problems/populating-next-right-pointers-in-each-node/)
@ -2472,6 +2624,36 @@ object Solution {
}
```
rust:
```rust
use std::cell::RefCell;
use std::collections::VecDeque;
use std::rc::Rc;
impl Solution {
pub fn max_depth(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {
let mut queue = VecDeque::new();
let mut res = 0;
if root.is_some() {
queue.push_back(root);
}
while !queue.is_empty() {
res += 1;
for _ in 0..queue.len() {
let node = queue.pop_front().unwrap().unwrap();
if node.borrow().left.is_some() {
queue.push_back(node.borrow().left.clone());
}
if node.borrow().right.is_some() {
queue.push_back(node.borrow().right.clone());
}
}
}
res
}
}
```
# 111.二叉树的最小深度
[力扣题目链接](https://leetcode.cn/problems/minimum-depth-of-binary-tree/)
@ -2716,6 +2898,39 @@ object Solution {
}
```
rust:
```rust
use std::cell::RefCell;
use std::collections::VecDeque;
use std::rc::Rc;
impl Solution {
pub fn min_depth(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {
let mut res = 0;
let mut queue = VecDeque::new();
if root.is_some() {
queue.push_back(root);
}
while !queue.is_empty() {
res += 1;
for _ in 0..queue.len() {
let node = queue.pop_front().unwrap().unwrap();
if node.borrow().left.is_none() && node.borrow().right.is_none() {
return res;
}
if node.borrow().left.is_some() {
queue.push_back(node.borrow().left.clone());
}
if node.borrow().right.is_some() {
queue.push_back(node.borrow().right.clone());
}
}
}
res
}
}
```
# 总结
二叉树的层序遍历,**就是图论中的广度优先搜索在二叉树中的应用**,需要借助队列来实现(此时又发现队列的一个应用了)。