Update 0106.从中序与后序遍历序列构造二叉树.md

添加 0106.从中序与后序遍历序列构造二叉树 Java版本
This commit is contained in:
Joshua
2021-05-14 00:56:39 +08:00
committed by GitHub
parent eded252643
commit dcda20261f

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@ -582,7 +582,41 @@ tree2 的前序遍历是[1 2 3] 后序遍历是[3 2 1]。
Java
```java
class Solution {
public TreeNode buildTree(int[] inorder, int[] postorder) {
return buildTree1(inorder, 0, inorder.length, postorder, 0, postorder.length);
}
public TreeNode buildTree1(int[] inorder, int inLeft, int inRight,
int[] postorder, int postLeft, int postRight) {
// 没有元素了
if (inRight - inLeft < 1) {
return null;
}
// 只有一个元素了
if (inRight - inLeft == 1) {
return new TreeNode(inorder[inLeft]);
}
// 后序数组postorder里最后一个即为根结点
int rootVal = postorder[postRight - 1];
TreeNode root = new TreeNode(rootVal);
int rootIndex = 0;
// 根据根结点的值找到该值在中序数组inorder里的位置
for (int i = inLeft; i < inRight; i++) {
if (inorder[i] == rootVal) {
rootIndex = i;
}
}
// 根据rootIndex划分左右子树
root.left = buildTree1(inorder, inLeft, rootIndex,
postorder, postLeft, postLeft + (rootIndex - inLeft));
root.right = buildTree1(inorder, rootIndex + 1, inRight,
postorder, postLeft + (rootIndex - inLeft), postRight - 1);
return root;
}
}
```
Python