diff --git a/problems/0019.删除链表的倒数第N个节点.md b/problems/0019.删除链表的倒数第N个节点.md
index e041937f..813e9b02 100644
--- a/problems/0019.删除链表的倒数第N个节点.md
+++ b/problems/0019.删除链表的倒数第N个节点.md
@@ -181,7 +181,71 @@ var removeNthFromEnd = function(head, n) {
return ret.next;
};
```
+TypeScript:
+
+版本一（快慢指针法）：
+
+```typescript
+function removeNthFromEnd(head: ListNode | null, n: number): ListNode | null {
+ let newHead: ListNode | null = new ListNode(0, head);
+ let slowNode: ListNode | null = newHead,
+ fastNode: ListNode | null = newHead;
+ for (let i = 0; i < n; i++) {
+ fastNode = fastNode.next;
+ }
+ while (fastNode.next) {
+ fastNode = fastNode.next;
+ slowNode = slowNode.next;
+ }
+ slowNode.next = slowNode.next.next;
+ return newHead.next;
+};
+```
+
+版本二（计算节点总数法）：
+
+```typescript
+function removeNthFromEnd(head: ListNode | null, n: number): ListNode | null {
+ let curNode: ListNode | null = head;
+ let listSize: number = 0;
+ while (curNode) {
+ curNode = curNode.next;
+ listSize++;
+ }
+ if (listSize === n) {
+ head = head.next;
+ } else {
+ curNode = head;
+ for (let i = 0; i < listSize - n - 1; i++) {
+ curNode = curNode.next;
+ }
+ curNode.next = curNode.next.next;
+ }
+ return head;
+};
+```
+
+版本三（递归倒退n法）：
+
+```typescript
+function removeNthFromEnd(head: ListNode | null, n: number): ListNode | null {
+ let newHead: ListNode | null = new ListNode(0, head);
+ let cnt = 0;
+ function recur(node) {
+ if (node === null) return;
+ recur(node.next);
+ cnt++;
+ if (cnt === n + 1) {
+ node.next = node.next.next;
+ }
+ }
+ recur(newHead);
+ return newHead.next;
+};
+```
+
Kotlin:
+
```Kotlin
fun removeNthFromEnd(head: ListNode?, n: Int): ListNode? {
val pre = ListNode(0).apply {
diff --git a/problems/0024.两两交换链表中的节点.md b/problems/0024.两两交换链表中的节点.md
index 01abc7b4..bf1fd5e1 100644
--- a/problems/0024.两两交换链表中的节点.md
+++ b/problems/0024.两两交换链表中的节点.md
@@ -250,6 +250,38 @@ var swapPairs = function (head) {
};
```
+TypeScript：
+
+```typescript
+function swapPairs(head: ListNode | null): ListNode | null {
+ /**
+ * 初始状态：
+ * curNode -> node1 -> node2 -> tmepNode
+ * 转换过程：
+ * curNode -> node2
+ * curNode -> node2 -> node1
+ * curNode -> node2 -> node1 -> tempNode
+ * curNode = node1
+ */
+ let retNode: ListNode | null = new ListNode(0, head),
+ curNode: ListNode | null = retNode,
+ node1: ListNode | null = null,
+ node2: ListNode | null = null,
+ tempNode: ListNode | null = null;
+
+ while (curNode && curNode.next && curNode.next.next) {
+ node1 = curNode.next;
+ node2 = curNode.next.next;
+ tempNode = node2.next;
+ curNode.next = node2;
+ node2.next = node1;
+ node1.next = tempNode;
+ curNode = node1;
+ }
+ return retNode.next;
+};
+```
+
Kotlin:
```kotlin
diff --git a/problems/0034.在排序数组中查找元素的第一个和最后一个位置.md b/problems/0034.在排序数组中查找元素的第一个和最后一个位置.md
index 2b96e41b..3f9cd747 100644
--- a/problems/0034.在排序数组中查找元素的第一个和最后一个位置.md
+++ b/problems/0034.在排序数组中查找元素的第一个和最后一个位置.md
@@ -389,6 +389,54 @@ class Solution:
### Go
```go
+func searchRange(nums []int, target int) []int {
+ leftBorder := searchLeftBorder(nums, target)
+ rightBorder := searchRightBorder(nums, target)
+
+ if leftBorder == -2 || rightBorder == -2 { // 情况一
+ return []int{-1, -1}
+ } else if rightBorder-leftBorder > 1 { // 情况三
+ return []int{leftBorder + 1, rightBorder - 1}
+ } else { // 情况二
+ return []int{-1, -1}
+ }
+}
+
+func searchLeftBorder(nums []int, target int) int {
+ left, right := 0, len(nums)-1
+ leftBorder := -2 // 记录一下leftBorder没有被赋值的情况
+ for left <= right {
+ middle := (left + right) / 2
+ if target == nums[middle] {
+ right = middle - 1
+ // 左边界leftBorder更新
+ leftBorder = right
+ } else if target > nums[middle] {
+ left = middle + 1
+ } else {
+ right = middle - 1
+ }
+ }
+ return leftBorder
+}
+
+func searchRightBorder(nums []int, target int) int {
+ left, right := 0, len(nums)-1
+ rightBorder := -2 // 记录一下rightBorder没有被赋值的情况
+ for left <= right {
+ middle := (left + right) / 2
+ if target == nums[middle] {
+ left = middle + 1
+ // 右边界rightBorder更新
+ rightBorder = left
+ } else if target > nums[middle] {
+ left = middle + 1
+ } else {
+ right = middle - 1
+ }
+ }
+ return rightBorder
+}
```
### JavaScript
diff --git a/problems/0101.对称二叉树.md b/problems/0101.对称二叉树.md
index b9dff99c..69bc41d3 100644
--- a/problems/0101.对称二叉树.md
+++ b/problems/0101.对称二叉树.md
@@ -574,7 +574,87 @@ var isSymmetric = function(root) {
};
```
+## Swift:
+> 递归
+```swift
+func isSymmetric(_ root: TreeNode?) -> Bool {
+ return _isSymmetric(root?.left, right: root?.right)
+}
+func _isSymmetric(_ left: TreeNode?, right: TreeNode?) -> Bool {
+ // 首先排除空节点情况
+ if left == nil && right == nil {
+ return true
+ } else if left == nil && right != nil {
+ return false
+ } else if left != nil && right == nil {
+ return false
+ } else if left!.val != right!.val {
+ // 进而排除数值不相等的情况
+ return false
+ }
+
+ // left 和 right 都不为空, 且数值也相等就递归
+ let inSide = _isSymmetric(left!.right, right: right!.left)
+ let outSide = _isSymmetric(left!.left, right: right!.right)
+ return inSide && outSide
+}
+```
+
+> 迭代 - 使用队列
+```swift
+func isSymmetric2(_ root: TreeNode?) -> Bool {
+ guard let root = root else {
+ return true
+ }
+ var queue = [TreeNode?]()
+ queue.append(root.left)
+ queue.append(root.right)
+ while !queue.isEmpty {
+ let left = queue.removeFirst()
+ let right = queue.removeFirst()
+ if left == nil && right == nil {
+ continue
+ }
+ if left == nil || right == nil || left?.val != right?.val {
+ return false
+ }
+ queue.append(left!.left)
+ queue.append(right!.right)
+ queue.append(left!.right)
+ queue.append(right!.left)
+ }
+ return true
+}
+```
+
+> 迭代 - 使用栈
+```swift
+func isSymmetric3(_ root: TreeNode?) -> Bool {
+ guard let root = root else {
+ return true
+ }
+ var stack = [TreeNode?]()
+ stack.append(root.left)
+ stack.append(root.right)
+ while !stack.isEmpty {
+ let left = stack.removeLast()
+ let right = stack.removeLast()
+
+ if left == nil && right == nil {
+ continue
+ }
+ if left == nil || right == nil || left?.val != right?.val {
+ return false
+ }
+ stack.append(left!.left)
+ stack.append(right!.right)
+ stack.append(left!.right)
+ stack.append(right!.left)
+ }
+ return true
+}
+```
-----------------------
diff --git a/problems/0104.二叉树的最大深度.md b/problems/0104.二叉树的最大深度.md
index 85b41548..7038598b 100644
--- a/problems/0104.二叉树的最大深度.md
+++ b/problems/0104.二叉树的最大深度.md
@@ -653,5 +653,82 @@ int maxDepth(struct TreeNode* root){
}
```
+## Swift
+
+>二叉树最大深度
+```swift
+// 递归 - 后序
+func maxDepth1(_ root: TreeNode?) -> Int {
+ return _maxDepth1(root)
+}
+func _maxDepth1(_ root: TreeNode?) -> Int {
+ if root == nil {
+ return 0
+ }
+ let leftDepth = _maxDepth1(root!.left)
+ let rightDepth = _maxDepth1(root!.right)
+ return 1 + max(leftDepth, rightDepth)
+}
+
+// 层序
+func maxDepth(_ root: TreeNode?) -> Int {
+ guard let root = root else {
+ return 0
+ }
+ var queue = [TreeNode]()
+ queue.append(root)
+ var res: Int = 0
+ while !queue.isEmpty {
+ res += 1
+ for _ in 0 ..< queue.count {
+ let node = queue.removeFirst()
+ if let left = node.left {
+ queue.append(left)
+ }
+ if let right = node.right {
+ queue.append(right)
+ }
+ }
+ }
+ return res
+}
+```
+
+>N叉树最大深度
+```swift
+// 递归
+func maxDepth(_ root: Node?) -> Int {
+ guard let root = root else {
+ return 0
+ }
+ var depth = 0
+ for node in root.children {
+ depth = max(depth, maxDepth(node))
+ }
+ return depth + 1
+}
+
+// 迭代-层序遍历
+func maxDepth1(_ root: Node?) -> Int {
+ guard let root = root else {
+ return 0
+ }
+ var depth = 0
+ var queue = [Node]()
+ queue.append(root)
+ while !queue.isEmpty {
+ let size = queue.count
+ depth += 1
+ for _ in 0 ..< size {
+ let node = queue.removeFirst()
+ for child in node.children {
+ queue.append(child)
+ }
+ }
+ }
+ return depth
+}
+```
+
-----------------------
diff --git a/problems/0111.二叉树的最小深度.md b/problems/0111.二叉树的最小深度.md
index fc93d918..a439322a 100644
--- a/problems/0111.二叉树的最小深度.md
+++ b/problems/0111.二叉树的最小深度.md
@@ -404,8 +404,51 @@ var minDepth = function(root) {
};
```
+## Swift
+> 递归
+```Swift
+func minDepth(_ root: TreeNode?) -> Int {
+ guard let root = root else {
+ return 0
+ }
+ if root.left == nil && root.right != nil {
+ return 1 + minDepth(root.right)
+ }
+ if root.left != nil && root.right == nil {
+ return 1 + minDepth(root.left)
+ }
+ return 1 + min(minDepth(root.left), minDepth(root.right))
+}
+```
+> 迭代
+```Swift
+func minDepth(_ root: TreeNode?) -> Int {
+ guard let root = root else {
+ return 0
+ }
+ var res = 0
+ var queue = [TreeNode]()
+ queue.append(root)
+ while !queue.isEmpty {
+ res += 1
+ for _ in 0 ..< queue.count {
+ let node = queue.removeFirst()
+ if node.left == nil && node.right == nil {
+ return res
+ }
+ if let left = node.left {
+ queue.append(left)
+ }
+ if let right = node.right {
+ queue.append(right)
+ }
+ }
+ }
+ return res
+}
+```
-----------------------
diff --git a/problems/0206.翻转链表.md b/problems/0206.翻转链表.md
index 13ed753c..941928ba 100644
--- a/problems/0206.翻转链表.md
+++ b/problems/0206.翻转链表.md
@@ -314,6 +314,54 @@ var reverseList = function(head) {
};
```
+TypeScript:
+
+```typescript
+// 双指针法
+function reverseList(head: ListNode | null): ListNode | null {
+ let preNode: ListNode | null = null,
+ curNode: ListNode | null = head,
+ tempNode: ListNode | null;
+ while (curNode) {
+ tempNode = curNode.next;
+ curNode.next = preNode;
+ preNode = curNode;
+ curNode = tempNode;
+ }
+ return preNode;
+};
+
+// 递归（从前往后翻转）
+function reverseList(head: ListNode | null): ListNode | null {
+ function recur(preNode: ListNode | null, curNode: ListNode | null): ListNode | null {
+ if (curNode === null) return preNode;
+ let tempNode: ListNode | null = curNode.next;
+ curNode.next = preNode;
+ preNode = curNode;
+ curNode = tempNode;
+ return recur(preNode, curNode);
+ }
+ return recur(null, head);
+};
+
+// 递归（从后往前翻转）
+function reverseList(head: ListNode | null): ListNode | null {
+ if (head === null) return null;
+ let newHead: ListNode | null;
+ function recur(node: ListNode | null, preNode: ListNode | null): void {
+ if (node.next === null) {
+ newHead = node;
+ newHead.next = preNode;
+ } else {
+ recur(node.next, node);
+ node.next = preNode;
+ }
+ }
+ recur(head, null);
+ return newHead;
+};
+```
+
Ruby:
```ruby
diff --git a/problems/0222.完全二叉树的节点个数.md b/problems/0222.完全二叉树的节点个数.md
index 754a6094..8d38bace 100644
--- a/problems/0222.完全二叉树的节点个数.md
+++ b/problems/0222.完全二叉树的节点个数.md
@@ -522,5 +522,73 @@ int countNodes(struct TreeNode* root){
}
```
+## Swift:
+
+> 递归
+```swift
+func countNodes(_ root: TreeNode?) -> Int {
+ return _countNodes(root)
+}
+func _countNodes(_ root: TreeNode?) -> Int {
+ guard let root = root else {
+ return 0
+ }
+ let leftCount = _countNodes(root.left)
+ let rightCount = _countNodes(root.right)
+ return 1 + leftCount + rightCount
+}
+```
+
+> 层序遍历
+```Swift
+func countNodes(_ root: TreeNode?) -> Int {
+ guard let root = root else {
+ return 0
+ }
+ var res = 0
+ var queue = [TreeNode]()
+ queue.append(root)
+ while !queue.isEmpty {
+ let size = queue.count
+ for _ in 0 ..< size {
+ let node = queue.removeFirst()
+ res += 1
+ if let left = node.left {
+ queue.append(left)
+ }
+ if let right = node.right {
+ queue.append(right)
+ }
+ }
+ }
+ return res
+}
+```
+
+> 利用完全二叉树性质
+```Swift
+func countNodes(_ root: TreeNode?) -> Int {
+ guard let root = root else {
+ return 0
+ }
+ var leftNode = root.left
+ var rightNode = root.right
+ var leftDepth = 0
+ var rightDepth = 0
+ while leftNode != nil {
+ leftNode = leftNode!.left
+ leftDepth += 1
+ }
+ while rightNode != nil {
+ rightNode = rightNode!.right
+ rightDepth += 1
+ }
+ if leftDepth == rightDepth {
+ return (2 << leftDepth) - 1
+ }
+ return countNodes(root.left) + countNodes(root.right) + 1
+}
+```
+
-----------------------
