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Update 1356.根据数字二进制下1的数目排序.md

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remove TODO for comparator
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hailincai
2021-09-05 09:45:39 -04:00
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parent adafd39931
commit d6f5a78587
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problems/1356.根据数字二进制下1的数目排序.md
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@ -139,7 +139,6 @@ class Solution {
.sorted(new Comparator<Integer>(){ .sorted(new Comparator<Integer>(){
@Override @Override
public int compare(Integer o1, Integer o2) { public int compare(Integer o1, Integer o2) {
// TODO Auto-generated method stub
int cnt1 = cntInt(o1); int cnt1 = cntInt(o1);
int cnt2 = cntInt(o2); int cnt2 = cntInt(o2);
return (cnt1 == cnt2) ? Integer.compare(o1, o2) : Integer.compare(cnt1, cnt2); return (cnt1 == cnt2) ? Integer.compare(o1, o2) : Integer.compare(cnt1, cnt2);