Merge pull request #725 from ironartisan/master

添加0530.二叉搜索树的最小绝对值差.md迭代Java解法
This commit is contained in:
程序员Carl
2021-09-09 11:07:44 +08:00
committed by GitHub
4 changed files with 100 additions and 1 deletions

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@ -234,7 +234,15 @@ public:
## Java
递归法:
```java
class Solution {
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
if (root.val > p.val && root.val > q.val) return lowestCommonAncestor(root.left, p, q);
if (root.val < p.val && root.val < q.val) return lowestCommonAncestor(root.right, p, q);
return root;
}
}
```
迭代法:
```java

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@ -293,6 +293,32 @@ class Solution {
}
}
```
```java
// 解法2
class Solution {
public TreeNode deleteNode(TreeNode root, int key) {
if (root == null) return root;
if (root.val == key) {
if (root.left == null) {
return root.right;
} else if (root.right == null) {
return root.left;
} else {
TreeNode cur = root.right;
while (cur.left != null) {
cur = cur.left;
}
cur.left = root.left;
root = root.right;
return root;
}
}
if (root.val > key) root.left = deleteNode(root.left, key);
if (root.val < key) root.right = deleteNode(root.right, key);
return root;
}
}
```
## Python

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@ -429,6 +429,44 @@ class Solution {
}
}
```
迭代法
```java
class Solution {
public int[] findMode(TreeNode root) {
TreeNode pre = null;
Stack<TreeNode> stack = new Stack<>();
List<Integer> result = new ArrayList<>();
int maxCount = 0;
int count = 0;
TreeNode cur = root;
while (cur != null || !stack.isEmpty()) {
if (cur != null) {
stack.push(cur);
cur =cur.left;
}else {
cur = stack.pop();
// 计数
if (pre == null || cur.val != pre.val) {
count = 1;
}else {
count++;
}
// 更新结果
if (count > maxCount) {
maxCount = count;
result.clear();
result.add(cur.val);
}else if (count == maxCount) {
result.add(cur.val);
}
pre = cur;
cur = cur.right;
}
}
return result.stream().mapToInt(Integer::intValue).toArray();
}
}
```
## Python

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@ -171,7 +171,34 @@ class Solution {
}
}
```
迭代法-中序遍历
```java
class Solution {
TreeNode pre;
Stack<TreeNode> stack;
public int getMinimumDifference(TreeNode root) {
if (root == null) return 0;
stack = new Stack<>();
TreeNode cur = root;
int result = Integer.MAX_VALUE;
while (cur != null || !stack.isEmpty()) {
if (cur != null) {
stack.push(cur); // 将访问的节点放进栈
cur = cur.left; // 左
}else {
cur = stack.pop();
if (pre != null) { // 中
result = Math.min(result, cur.val - pre.val);
}
pre = cur;
cur = cur.right; // 右
}
}
return result;
}
}
```
## Python
递归