添加 0078.子集.md Scala版本

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ZongqinWang
2022-06-05 13:50:27 +08:00
parent be18cd3961
commit ccfb805417

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@ -373,6 +373,60 @@ func subsets(_ nums: [Int]) -> [[Int]] {
} }
``` ```
## Scala
思路一: 使用本题解思路
```scala
object Solution {
import scala.collection.mutable
def subsets(nums: Array[Int]): List[List[Int]] = {
var result = mutable.ListBuffer[List[Int]]()
var path = mutable.ListBuffer[Int]()
def backtracking(startIndex: Int): Unit = {
result.append(path.toList) // 存放结果
if (startIndex >= nums.size) {
return
}
for (i <- startIndex until nums.size) {
path.append(nums(i)) // 添加元素
backtracking(i + 1)
path.remove(path.size - 1) // 删除
}
}
backtracking(0)
result.toList
}
}
```
思路二: 将原问题转换为二叉树,针对每一个元素都有**选或不选**两种选择,直到遍历到最后,所有的叶子节点即为本题的答案:
```scala
object Solution {
import scala.collection.mutable
def subsets(nums: Array[Int]): List[List[Int]] = {
var result = mutable.ListBuffer[List[Int]]()
def backtracking(path: mutable.ListBuffer[Int], startIndex: Int): Unit = {
if (startIndex == nums.length) {
result.append(path.toList)
return
}
path.append(nums(startIndex))
backtracking(path, startIndex + 1) // 选择元素
path.remove(path.size - 1)
backtracking(path, startIndex + 1) // 不选择元素
}
backtracking(mutable.ListBuffer[Int](), 0)
result.toList
}
}
```
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<div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div> <div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>