diff --git a/problems/0746.使用最小花费爬楼梯.md b/problems/0746.使用最小花费爬楼梯.md index d7258d45..31e7bd48 100644 --- a/problems/0746.使用最小花费爬楼梯.md +++ b/problems/0746.使用最小花费爬楼梯.md @@ -312,17 +312,30 @@ func min(a, b int) int { ``` -### Javascript -```Javascript +### JavaScript + +```JavaScript var minCostClimbingStairs = function(cost) { - const n = cost.length; - const dp = new Array(n + 1); - dp[0] = dp[1] = 0; - for (let i = 2; i <= n; ++i) { - dp[i] = Math.min(dp[i -1] + cost[i - 1], dp[i - 2] + cost[i - 2]) + const dp = [0, 0] + for (let i = 2; i <= cost.length; ++i) { + dp[i] = Math.min(dp[i - 1] + cost[i - 1], dp[i - 2] + cost[i - 2]) + } + return dp[cost.length] +}; +``` + +不使用 dp 数组 + +```JavaScript +var minCostClimbingStairs = function(cost) { + let dpBefore = 0, + dpAfter = 0 + for(let i = 2;i <= cost.length;i++){ + let dpi = Math.min(dpBefore + cost[i - 2],dpAfter + cost[i - 1]) + dpBefore = dpAfter + dpAfter = dpi } - - return dp[n] + return dpAfter }; ``` @@ -330,38 +343,55 @@ var minCostClimbingStairs = function(cost) { ```typescript function minCostClimbingStairs(cost: number[]): number { - /** - dp[i]: 走到第i阶需要花费的最少金钱 - dp[0]: 0; - dp[1]: 0; - ... - dp[i]: min(dp[i - 1] + cost[i - 1], dp[i - 2] + cost[i - 2]); - */ - const dp = []; - const length = cost.length; - dp[0] = 0; - dp[1] = 0; - for (let i = 2; i <= length; i++) { - dp[i] = Math.min(dp[i - 1] + cost[i - 1], dp[i - 2] + cost[i - 2]); - } - return dp[length]; -}; + const dp = [0, 0] + for (let i = 2; i <= cost.length; i++) { + dp[i] = Math.min(dp[i - 1] + cost[i - 1], dp[i - 2] + cost[i - 2]) + } + return dp[cost.length] +} +``` + +不使用 dp 数组 + +```typescript +function minCostClimbingStairs(cost: number[]): number { + let dpBefore = 0, + dpAfter = 0 + for (let i = 2; i <= cost.length; i++) { + let dpi = Math.min(dpBefore + cost[i - 2], dpAfter + cost[i - 1]) + dpBefore = dpAfter + dpAfter = dpi + } + return dpAfter +} ``` ### Rust ```Rust -use std::cmp::min; impl Solution { pub fn min_cost_climbing_stairs(cost: Vec) -> i32 { - let len = cost.len(); - let mut dp = vec![0; len]; - dp[0] = cost[0]; - dp[1] = cost[1]; - for i in 2..len { - dp[i] = min(dp[i-1], dp[i-2]) + cost[i]; + let mut dp = vec![0; cost.len() + 1]; + for i in 2..=cost.len() { + dp[i] = (dp[i - 1] + cost[i - 1]).min(dp[i - 2] + cost[i - 2]); } - min(dp[len-1], dp[len-2]) + dp[cost.len()] + } +} +``` + +不使用 dp 数组 + +```rust +impl Solution { + pub fn min_cost_climbing_stairs(cost: Vec) -> i32 { + let (mut dp_before, mut dp_after) = (0, 0); + for i in 2..=cost.len() { + let dpi = (dp_before + cost[i - 2]).min(dp_after + cost[i - 1]); + dp_before = dp_after; + dp_after = dpi; + } + dp_after } } ``` @@ -369,18 +399,29 @@ impl Solution { ### C ```c -int minCostClimbingStairs(int* cost, int costSize){ - //开辟dp数组,大小为costSize - int *dp = (int *)malloc(sizeof(int) * costSize); - //初始化dp[0] = cost[0], dp[1] = cost[1] - dp[0] = cost[0], dp[1] = cost[1]; +#include +int minCostClimbingStairs(int *cost, int costSize) { + int dp[costSize + 1]; + dp[0] = dp[1] = 0; + for (int i = 2; i <= costSize; i++) { + dp[i] = fmin(dp[i - 2] + cost[i - 2], dp[i - 1] + cost[i - 1]); + } + return dp[costSize]; +} +``` - int i; - for(i = 2; i < costSize; ++i) { - dp[i] = (dp[i-1] < dp[i-2] ? dp[i-1] : dp[i-2]) + cost[i]; - } - //选出倒数2层楼梯中较小的 - return dp[i-1] < dp[i-2] ? dp[i-1] : dp[i-2]; +不使用 dp 数组 + +```c +#include +int minCostClimbingStairs(int *cost, int costSize) { + int dpBefore = 0, dpAfter = 0; + for (int i = 2; i <= costSize; i++) { + int dpi = fmin(dpBefore + cost[i - 2], dpAfter + cost[i - 1]); + dpBefore = dpAfter; + dpAfter = dpi; + } + return dpAfter; } ```