From 7aa230ed40e7583a61ec6b6fb38500b17c0dfe27 Mon Sep 17 00:00:00 2001
From: wangya <1264178545@qq.com>
Date: Wed, 17 Jul 2024 14:13:19 +0800
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---
 problems/kamacoder/0098.所有可达路径.md | 146 +++++++++++++++++-
 1 file changed, 142 insertions(+), 4 deletions(-)

diff --git a/problems/kamacoder/0098.所有可达路径.md b/problems/kamacoder/0098.所有可达路径.md
index 073d1a2e..3281303d 100644
--- a/problems/kamacoder/0098.所有可达路径.md
+++ b/problems/kamacoder/0098.所有可达路径.md
@@ -75,7 +75,7 @@
 
 ## 插曲  
 
-------------- 
+-------------
 
 本题和力扣 [797.所有可能的路径](https://leetcode.cn/problems/all-paths-from-source-to-target/description/) 是一样的，录友了解深度优先搜索之后，这道题目就是模板题，是送分题。
 
@@ -475,7 +475,7 @@ public class Main {
         }
     }
 }
-```  
+```
 
 #### 邻接表写法
 ```java
@@ -564,7 +564,7 @@ def main():
 
 if __name__ == "__main__":
     main()
-```  
+```
 
 #### 邻接表写法
 ``` python
@@ -608,6 +608,145 @@ if __name__ == "__main__":
 
 ### Javascript
 
+#### 邻接矩阵写法
+
+```javascript
+const r1 = require('readline').createInterface({ input: process.stdin });
+// 创建readline接口
+let iter = r1[Symbol.asyncIterator]();
+// 创建异步迭代器
+const readline = async ()=>(await iter.next()).value;
+
+
+let graph;
+let N, M;
+// 收集符合条件的路径
+let result = [];
+// 1节点到终点的路径
+let path = [];
+
+// 创建邻接矩阵，初始化邻接矩阵
+async function initGraph(){
+    let line;
+
+    line = await readline();
+    [N, M] = line.split(' ').map(i => parseInt(i))
+    graph = new Array(N + 1).fill(0).map(() => new Array(N + 1).fill(0))
+    
+    while(M--){
+        line = await readline()
+        const strArr = line ?  line.split(' ').map(i => parseInt(i)) : undefined
+        strArr ? graph[strArr[0]][strArr[1]] = 1 : null
+    }
+};
+
+// 深度搜索
+function dfs(graph, x,  n){
+    // 当前遍历节点为x， 到达节点为n
+    if(x == n){
+        result.push([...path])
+        return
+    }
+    for(let i = 1 ; i <= n ; i++){
+        if(graph[x][i] == 1){
+            path.push(i)
+            dfs(graph, i, n )
+            path.pop(i)
+        }
+    }
+};
+
+(async function(){
+    // 创建邻接矩阵，初始化邻接矩阵
+    await initGraph();
+    
+    // 从节点1开始深度搜索
+    path.push(1);
+    
+    // 深度搜索
+    dfs(graph, 1, N );
+    
+    // 输出
+    if(result.length > 0){
+        result.forEach(i => {
+            console.log(i.join(' '))
+        })
+    }else{
+        console.log(-1)
+    }
+   
+})();
+
+```
+
+
+
+#### 邻接表写法
+
+```javascript
+const r1 = require('readline').createInterface({ input: process.stdin });
+// 创建readline接口
+let iter = r1[Symbol.asyncIterator]();
+// 创建异步迭代器
+const readline = async () => (await iter.next()).value;
+
+let graph;
+let N, M;
+
+// 收集符合条件的路径
+let result = [];
+// 1节点到终点的路径
+let path = [];
+
+// 创建邻接表，初始化邻接表
+async function initGraph() {
+  let line;
+  line = await readline();
+  [N, M] = line.split(' ').map(i => parseInt(i))
+  graph = new Array(N + 1).fill(0).map(() => new Array())
+
+  while (line = await readline()) {
+    const strArr = line.split(' ').map(i => parseInt(i))
+    strArr ? graph[strArr[0]].push(strArr[1]) : null
+  }
+};
+
+// 深度搜索
+async function dfs(graph, x, n) {
+  // 当前遍历节点为x， 到达节点为n
+  if (x == n) {
+    result.push([...path])
+    return
+  }
+
+  graph[x].forEach(i => {
+    path.push(i)
+    dfs(graph, i, n)
+    path.pop(i)
+  })
+};
+
+(async function () {
+  // 创建邻接表，初始化邻接表
+  await initGraph();
+
+  // 从节点1开始深度搜索
+  path.push(1);
+
+  // 深度搜索
+  dfs(graph, 1, N);
+
+  // 输出
+  if (result.length > 0) {
+    result.forEach(i => {
+      console.log(i.join(' '))
+    })
+  } else {
+    console.log(-1)
+  }
+})();
+```
+
 ### TypeScript
 
 ### PhP
@@ -628,4 +767,3 @@ if __name__ == "__main__":
 
 
 
-