diff --git a/problems/kamacoder/0097.小明逛公园.md b/problems/kamacoder/0097.小明逛公园.md
index 5465c356..e8d92cc2 100644
--- a/problems/kamacoder/0097.小明逛公园.md
+++ b/problems/kamacoder/0097.小明逛公园.md
@@ -339,7 +339,7 @@ int main() {
     }
 }
 
-``` 
+```
 
 ## 空间优化
 
@@ -426,6 +426,68 @@ floyd算法的时间复杂度相对较高，适合 稠密图且源点较多的
 
 ### Python
 
+基于三维数组的Floyd
+
+```python
+if __name__ == '__main__':
+    max_int = 10005  # 设置最大路径，因为边最大距离为10^4
+
+    n, m = map(int, input().split())
+
+    grid = [[[max_int] * (n+1) for _ in range(n+1)] for _ in range(n+1)]  # 初始化三维dp数组
+
+    for _ in range(m):
+        p1, p2, w = map(int, input().split())
+        grid[p1][p2][0] = w
+        grid[p2][p1][0] = w
+
+    # 开始floyd
+    for k in range(1, n+1):
+        for i in range(1, n+1):
+            for j in range(1, n+1):
+                grid[i][j][k] = min(grid[i][j][k-1], grid[i][k][k-1] + grid[k][j][k-1])
+
+    # 输出结果
+    z = int(input())
+    for _ in range(z):
+        start, end = map(int, input().split())
+        if grid[start][end][n] == max_int:
+            print(-1)
+        else:
+            print(grid[start][end][n])
+```
+
+基于二维数组的Floyd
+
+```python
+if __name__ == '__main__':
+    max_int = 10005  # 设置最大路径，因为边最大距离为10^4
+
+    n, m = map(int, input().split())
+
+    grid = [[max_int]*(n+1) for _ in range(n+1)]  # 初始化二维dp数组
+
+    for _ in range(m):
+        p1, p2, val = map(int, input().split())
+        grid[p1][p2] = val
+        grid[p2][p1] = val
+
+    # 开始floyd
+    for k in range(1, n+1):
+        for i in range(1, n+1):
+            for j in range(1, n+1):
+                grid[i][j] = min(grid[i][j], grid[i][k] + grid[k][j])
+
+    # 输出结果
+    z = int(input())
+    for _ in range(z):
+        start, end = map(int, input().split())
+        if grid[start][end] == max_int:
+            print(-1)
+        else:
+            print(grid[start][end])
+```
+
 ### Go
 
 ### Rust
diff --git a/problems/kamacoder/0099.岛屿的数量深搜.md b/problems/kamacoder/0099.岛屿的数量深搜.md
index 46f7e779..b257ca9a 100644
--- a/problems/kamacoder/0099.岛屿的数量深搜.md
+++ b/problems/kamacoder/0099.岛屿的数量深搜.md
@@ -185,6 +185,100 @@ int main() {
 
 ### Python
 
+版本一
+
+```python
+direction = [[0, 1], [1, 0], [0, -1], [-1, 0]]  # 四个方向：上、右、下、左
+
+
+def dfs(grid, visited, x, y):
+    """
+    对一块陆地进行深度优先遍历并标记
+    """
+    for i, j in direction:
+        next_x = x + i
+        next_y = y + j
+        # 下标越界，跳过
+        if next_x < 0 or next_x >= len(grid) or next_y < 0 or next_y >= len(grid[0]):
+            continue
+        # 未访问的陆地，标记并调用深度优先搜索
+        if not visited[next_x][next_y] and grid[next_x][next_y] == 1:
+            visited[next_x][next_y] = True
+            dfs(grid, visited, next_x, next_y)
+
+
+if __name__ == '__main__':  
+    # 版本一
+    n, m = map(int, input().split())
+    
+    # 邻接矩阵
+    grid = []
+    for i in range(n):
+        grid.append(list(map(int, input().split())))
+    
+    # 访问表
+    visited = [[False] * m for _ in range(n)]
+    
+    res = 0
+    for i in range(n):
+        for j in range(m):
+            # 判断：如果当前节点是陆地，res+1并标记访问该节点，使用深度搜索标记相邻陆地。
+            if grid[i][j] == 1 and not visited[i][j]:
+                res += 1
+                visited[i][j] = True
+                dfs(grid, visited, i, j)
+    
+    print(res)
+```
+
+版本二
+
+```python
+direction = [[0, 1], [1, 0], [0, -1], [-1, 0]]  # 四个方向：上、右、下、左
+
+
+def dfs(grid, visited, x, y):
+    """
+    对一块陆地进行深度优先遍历并标记
+    """
+    # 与版本一的差别，在调用前增加判断终止条件
+    if visited[x][y] or grid[x][y] == 0:
+        return
+    visited[x][y] = True
+
+    for i, j in direction:
+        next_x = x + i
+        next_y = y + j
+        # 下标越界，跳过
+        if next_x < 0 or next_x >= len(grid) or next_y < 0 or next_y >= len(grid[0]):
+            continue
+        # 由于判断条件放在了方法首部，此处直接调用dfs方法
+        dfs(grid, visited, next_x, next_y)
+
+
+if __name__ == '__main__':
+    # 版本二
+    n, m = map(int, input().split())
+
+    # 邻接矩阵
+    grid = []
+    for i in range(n):
+        grid.append(list(map(int, input().split())))
+
+    # 访问表
+    visited = [[False] * m for _ in range(n)]
+
+    res = 0
+    for i in range(n):
+        for j in range(m):
+            # 判断：如果当前节点是陆地，res+1并标记访问该节点，使用深度搜索标记相邻陆地。
+            if grid[i][j] == 1 and not visited[i][j]:
+                res += 1
+                dfs(grid, visited, i, j)
+
+    print(res)
+```
+
 ### Go
 
 ### Rust