From ba3c7ec19b6b2ad3f95f35ae55f25b2459d710b3 Mon Sep 17 00:00:00 2001
From: jianghongcheng <35664721+jianghongcheng@users.noreply.github.com>
Date: Thu, 1 Jun 2023 01:37:41 -0500
Subject: [PATCH] =?UTF-8?q?Update=200860.=E6=9F=A0=E6=AA=AC=E6=B0=B4?=
 =?UTF-8?q?=E6=89=BE=E9=9B=B6.md?=
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---
 problems/0860.柠檬水找零.md | 31 +++++++++++++++++++++++--------
 1 file changed, 23 insertions(+), 8 deletions(-)

diff --git a/problems/0860.柠檬水找零.md b/problems/0860.柠檬水找零.md
index d96e0879..5046df12 100644
--- a/problems/0860.柠檬水找零.md
+++ b/problems/0860.柠檬水找零.md
@@ -164,24 +164,39 @@ class Solution {
 ```python
 class Solution:
     def lemonadeChange(self, bills: List[int]) -> bool:
-        five, ten = 0, 0
+        five = 0
+        ten = 0
+        twenty = 0
+        
         for bill in bills:
+            # 情况一：收到5美元
             if bill == 5:
                 five += 1
-            elif bill == 10:
-                if five < 1: return False
-                five -= 1
+            
+            # 情况二：收到10美元
+            if bill == 10:
+                if five <= 0:
+                    return False
                 ten += 1
-            else:
-                if ten > 0 and five > 0:
-                    ten -= 1
+                five -= 1
+            
+            # 情况三：收到20美元
+            if bill == 20:
+                # 先尝试使用10美元和5美元找零
+                if five > 0 and ten > 0:
                     five -= 1
-                elif five > 2:
+                    ten -= 1
+                    #twenty += 1
+                # 如果无法使用10美元找零，则尝试使用三张5美元找零
+                elif five >= 3:
                     five -= 3
+                    #twenty += 1
                 else:
                     return False
+        
         return True
 
+
 ```
 
 ### Go