mirror of
https://github.com/youngyangyang04/leetcode-master.git
synced 2025-07-09 19:44:45 +08:00
添加0459.重复的子字符串Java版本
This commit is contained in:
@ -149,9 +149,38 @@ public:
|
||||
|
||||
## 其他语言版本
|
||||
|
||||
|
||||
Java:
|
||||
|
||||
```java
|
||||
class Solution {
|
||||
public boolean repeatedSubstringPattern(String s) {
|
||||
if (s.equals("")) return false;
|
||||
|
||||
int len = s.length();
|
||||
// 原串加个空格(哨兵),使下标从1开始,这样j从0开始,也不用初始化了
|
||||
s = " " + s;
|
||||
char[] chars = s.toCharArray();
|
||||
int[] next = new int[len + 1];
|
||||
|
||||
// 构造 next 数组过程,j从0开始(空格),i从2开始
|
||||
for (int i = 2, j = 0; i <= len; i++) {
|
||||
// 匹配不成功,j回到前一位置 next 数组所对应的值
|
||||
while (j > 0 && chars[i] != chars[j + 1]) j = next[j];
|
||||
// 匹配成功,j往后移
|
||||
if (chars[i] == chars[j + 1]) j++;
|
||||
// 更新 next 数组的值
|
||||
next[i] = j;
|
||||
}
|
||||
|
||||
// 最后判断是否是重复的子字符串,这里 next[len] 即代表next数组末尾的值
|
||||
if (next[len] > 0 && len % (len - next[len]) == 0) {
|
||||
return true;
|
||||
}
|
||||
return false;
|
||||
}
|
||||
}
|
||||
```
|
||||
|
||||
|
||||
Python:
|
||||
|
||||
|
Reference in New Issue
Block a user