From 985055c2e2a45a9b56f97b5868e0f8548274bb93 Mon Sep 17 00:00:00 2001 From: Arthur Date: Thu, 23 Sep 2021 10:43:51 +0100 Subject: [PATCH] =?UTF-8?q?=E6=B7=BB=E5=8A=A0=200090.=E5=AD=90=E9=9B=86II.?= =?UTF-8?q?md=20C=E8=AF=AD=E8=A8=80=E7=89=88=E6=9C=AC?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- problems/0090.子集II.md | 68 +++++++++++++++++++++++++++++++++++++++ 1 file changed, 68 insertions(+) diff --git a/problems/0090.子集II.md b/problems/0090.子集II.md index 6dc631de..ff5eb14d 100644 --- a/problems/0090.子集II.md +++ b/problems/0090.子集II.md @@ -279,6 +279,74 @@ var subsetsWithDup = function(nums) { ``` +C: +```c +int* path; +int pathTop; +int** ans; +int ansTop; +//负责存放二维数组中每个数组的长度 +int* lengths; +//快排cmp函数 +int cmp(const void* a, const void* b) { + return *((int*)a) - *((int*)b); +} + +//复制函数,将当前path中的元素复制到ans中。同时记录path长度 +void copy() { + int* tempPath = (int*)malloc(sizeof(int) * pathTop); + int i; + for(i = 0; i < pathTop; i++) { + tempPath[i] = path[i]; + } + ans = (int**)realloc(ans, sizeof(int*) * (ansTop + 1)); + lengths[ansTop] = pathTop; + ans[ansTop++] = tempPath; +} + +void backTracking(int* nums, int numsSize, int startIndex, int* used) { + //首先将当前path复制 + copy(); + //若startIndex大于数组最后一位元素的位置,返回 + if(startIndex >= numsSize) + return ; + + int i; + for(i = startIndex; i < numsSize; i++) { + //对同一树层使用过的元素进行跳过 + if(i > 0 && nums[i] == nums[i-1] && used[i-1] == false) + continue; + path[pathTop++] = nums[i]; + used[i] = true; + backTracking(nums, numsSize, i + 1, used); + used[i] = false; + pathTop--; + } +} + +int** subsetsWithDup(int* nums, int numsSize, int* returnSize, int** returnColumnSizes){ + //声明辅助变量 + path = (int*)malloc(sizeof(int) * numsSize); + ans = (int**)malloc(0); + lengths = (int*)malloc(sizeof(int) * 1500); + int* used = (int*)malloc(sizeof(int) * numsSize); + pathTop = ansTop = 0; + + //排序后查重才能生效 + qsort(nums, numsSize, sizeof(int), cmp); + backTracking(nums, numsSize, 0, used); + + //设置一维数组和二维数组的返回大小 + *returnSize = ansTop; + *returnColumnSizes = (int*)malloc(sizeof(int) * ansTop); + int i; + for(i = 0; i < ansTop; i++) { + (*returnColumnSizes)[i] = lengths[i]; + } + return ans; +} +``` + -----------------------