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Merge pull request #1726 from asiL-tcefreP/master

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Update 0084.柱状图中最大的矩形.md (Java版本)
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程序员Carl
2022-11-12 13:19:41 +08:00
committed by GitHub
parent 289e58b9b8 2df651a135
commit b56bc32a23
1 changed files with 6 additions and 6 deletions
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problems/0084.柱状图中最大的矩形.md
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@ -206,7 +206,7 @@ class Solution {
public int largestRectangleArea(int[] heights) {
int length = heights.length;
int[] minLeftIndex = new int [length];
int[] maxRigthIndex = new int [length];
int[] minRightIndex = new int [length];
// 记录左边第一个小于该柱子的下标
minLeftIndex[0] = -1 ;
for (int i = 1; i < length; i++) {
@ -215,17 +215,17 @@ class Solution {
while (t >= 0 && heights[t] >= heights[i]) t = minLeftIndex[t];
minLeftIndex[i] = t;
}
// 记录每个柱子 右边第一个小于该柱子的下标
maxRigthIndex[length - 1] = length;
// 记录每个柱子右边第一个小于该柱子的下标
minRightIndex[length - 1] = length;
for (int i = length - 2; i >= 0; i--) {
int t = i + 1;
while(t < length && heights[t] >= heights[i]) t = maxRigthIndex[t];
maxRigthIndex[i] = t;
while(t < length && heights[t] >= heights[i]) t = minRightIndex[t];
minRightIndex[i] = t;
}
// 求和
int result = 0;
for (int i = 0; i < length; i++) {
int sum = heights[i] * (maxRigthIndex[i] - minLeftIndex[i] - 1);
int sum = heights[i] * (minRightIndex[i] - minLeftIndex[i] - 1);
result = Math.max(sum, result);
}
return result;