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更新 0509.斐波那契数 排版格式修复
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@ -32,9 +32,9 @@ F(n) = F(n - 1) + F(n - 2),其中 n > 1
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* 0 <= n <= 30
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* 0 <= n <= 30
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# 视频讲解
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## 算法公开课
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**《代码随想录》算法视频公开课:[手把手带你入门动态规划 | leetcode:509.斐波那契数](https://www.bilibili.com/video/BV1f5411K7mo),相信结合视频在看本篇题解,更有助于大家对本题的理解**。
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**[《代码随想录》算法视频公开课](https://programmercarl.com/other/gongkaike.html):[手把手带你入门动态规划 | leetcode:509.斐波那契数](https://www.bilibili.com/video/BV1f5411K7mo),相信结合视频在看本篇题解,更有助于大家对本题的理解**。
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## 思路
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## 思路
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@ -278,7 +278,7 @@ class Solution:
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return self.fib(n - 1) + self.fib(n - 2)
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return self.fib(n - 1) + self.fib(n - 2)
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```
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```
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### Go:
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### Go
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```Go
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```Go
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func fib(n int) int {
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func fib(n int) int {
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if n < 2 {
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if n < 2 {
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@ -479,3 +479,4 @@ public class Solution
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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<img src="../pics/网站星球宣传海报.jpg" width="1000"/>
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<img src="../pics/网站星球宣传海报.jpg" width="1000"/>
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</a>
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</a>
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