From ad1faf8a150a8954661e39cbd25f0fdc1b1f8b5b Mon Sep 17 00:00:00 2001 From: kok-s0s <2694308562@qq.com> Date: Fri, 25 Jun 2021 22:54:40 +0800 Subject: [PATCH] =?UTF-8?q?=E6=8F=90=E4=BE=9BJavaScript=E7=89=88=E6=9C=AC?= =?UTF-8?q?=E7=9A=84=E3=80=8A=E4=BA=8C=E5=8F=89=E6=90=9C=E7=B4=A2=E6=A0=91?= =?UTF-8?q?=E4=B8=AD=E7=9A=84=E6=8F=92=E5=85=A5=E6=93=8D=E4=BD=9C=E3=80=8B?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- .../0701.二叉搜索树中的插入操作.md | 77 +++++++++++++++++++ 1 file changed, 77 insertions(+) diff --git a/problems/0701.二叉搜索树中的插入操作.md b/problems/0701.二叉搜索树中的插入操作.md index 0f5b603a..794e0ae2 100644 --- a/problems/0701.二叉搜索树中的插入操作.md +++ b/problems/0701.二叉搜索树中的插入操作.md @@ -320,7 +320,84 @@ var insertIntoBST = function (root, val) { }; ``` +> 无返回值的递归 +```javascript +/** + * Definition for a binary tree node. + * function TreeNode(val, left, right) { + * this.val = (val===undefined ? 0 : val) + * this.left = (left===undefined ? null : left) + * this.right = (right===undefined ? null : right) + * } + */ +/** + * @param {TreeNode} root + * @param {number} val + * @return {TreeNode} + */ +var insertIntoBST = function (root, val) { + let parent = new TreeNode(0); + const preOrder = (cur, val) => { + if (cur === null) { + let node = new TreeNode(val); + if (parent.val > val) + parent.left = node; + else + parent.right = node; + return; + } + parent = cur; + if (cur.val > val) + preOrder(cur.left, val); + if (cur.val < val) + preOrder(cur.right, val); + } + if (root === null) + root = new TreeNode(val); + preOrder(root, val); + return root; +}; +``` + +> 迭代 + +```javascript +/** + * Definition for a binary tree node. + * function TreeNode(val, left, right) { + * this.val = (val===undefined ? 0 : val) + * this.left = (left===undefined ? null : left) + * this.right = (right===undefined ? null : right) + * } + */ +/** + * @param {TreeNode} root + * @param {number} val + * @return {TreeNode} + */ +var insertIntoBST = function (root, val) { + if (root === null) { + root = new TreeNode(val); + } else { + let parent = new TreeNode(0); + let cur = root; + while (cur) { + parent = cur; + if (cur.val > val) + cur = cur.left; + else + cur = cur.right; + } + let node = new TreeNode(val); + if (parent.val > val) + parent.left = node; + else + parent.right = node; + } + return root; +}; +``` ----------------------- * 作者微信:[程序员Carl](https://mp.weixin.qq.com/s/b66DFkOp8OOxdZC_xLZxfw)