From ac40cc8be29fdbf22b2b6a5b889315de74f602c3 Mon Sep 17 00:00:00 2001
From: KailokFung <jialuo_feng@foxmail.com>
Date: Wed, 23 Jun 2021 10:24:40 +0800
Subject: [PATCH] =?UTF-8?q?fix(1047):=20=E6=96=B0=E5=A2=9E=E5=8F=8C?=
 =?UTF-8?q?=E6=8C=87=E9=92=88java=E5=86=99=E6=B3=95?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

---
 ...除字符串中的所有相邻重复项.md | 23 +++++++++++++++++++
 1 file changed, 23 insertions(+)

diff --git a/problems/1047.删除字符串中的所有相邻重复项.md b/problems/1047.删除字符串中的所有相邻重复项.md
index 305a287d..4f13cda3 100644
--- a/problems/1047.删除字符串中的所有相邻重复项.md
+++ b/problems/1047.删除字符串中的所有相邻重复项.md
@@ -171,6 +171,29 @@ class Solution {
 }
 ```
 
+拓展：双指针
+```java
+class Solution {
+    public String removeDuplicates(String s) {
+        char[] ch = s.toCharArray();
+        int fast = 0;
+        int slow = 0;
+        while(fast < s.length()){
+            // 直接用fast指针覆盖slow指针的值
+            ch[slow] = ch[fast];
+            // 遇到前后相同值的，就跳过，即slow指针后退一步，下次循环就可以直接被覆盖掉了
+            if(slow > 0 && ch[slow] == ch[slow - 1]){
+                slow--;
+            }else{
+                slow++;
+            }
+            fast++;
+        }
+        return new String(ch,0,slow);
+    }
+}
+```
+
 Python：
 ```python3
 class Solution: