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Update 102.二叉树的层序遍历，添加C#版

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2023-11-14 09:11:17 +08:00
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51
problems/0102.二叉树的层序遍历.md
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@ -462,6 +462,32 @@ impl Solution {
} }
} }
``` ```
### C#
```C#
public IList<IList<int>> LevelOrder(TreeNode root)
{
var res = new List<IList<int>>();
var que = new Queue<TreeNode>();
if (root == null) return res;
que.Enqueue(root);
while (que.Count != 0)
{
var size = que.Count;
var vec = new List<int>();
for (int i = 0; i < size; i++)
{
var cur = que.Dequeue();
vec.Add(cur.val);
if (cur.left != null) que.Enqueue(cur.left);
if (cur.right != null) que.Enqueue(cur.right);
}
res.Add(vec);
}
return res;
}
```
**此时我们就掌握了二叉树的层序遍历了，那么如下九道力扣上的题目，只需要修改模板的两三行代码（不能再多了），便可打倒！** **此时我们就掌握了二叉树的层序遍历了，那么如下九道力扣上的题目，只需要修改模板的两三行代码（不能再多了），便可打倒！**
@ -798,6 +824,31 @@ impl Solution {
} }
} }
``` ```
### C#
```C#
public IList<IList<int>> LevelOrderBottom(TreeNode root)
{
var res = new List<IList<int>>();
var que = new Queue<TreeNode>();
if (root == null) return res;
que.Enqueue(root);
while (que.Count != 0)
{
var size = que.Count;
var vec = new List<int>();
for (int i = 0; i < size; i++)
{
var cur = que.Dequeue();
vec.Add(cur.val);
if (cur.left != null) que.Enqueue(cur.left);
if (cur.right != null) que.Enqueue(cur.right);
}
res.Add(vec);
}
res.Reverse();
return res;
}
```
## 199.二叉树的右视图 ## 199.二叉树的右视图