From aa4ce0f096013a20847b4b7c325a22fbe26e6deb Mon Sep 17 00:00:00 2001
From: ironartisan <ironerhalo@gmail.com>
Date: Thu, 19 Aug 2021 15:03:44 +0800
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---
 problems/0279.完全平方数.md | 27 ++++++++++++++++++++++++++-
 1 file changed, 26 insertions(+), 1 deletion(-)

diff --git a/problems/0279.完全平方数.md b/problems/0279.完全平方数.md
index 863bd60c..f23453da 100644
--- a/problems/0279.完全平方数.md
+++ b/problems/0279.完全平方数.md
@@ -161,6 +161,7 @@ public:
 Java：
 ```Java
 class Solution {
+    // 版本一，先遍历物品, 再遍历背包
     public int numSquares(int n) {
         int max = Integer.MAX_VALUE;
         int[] dp = new int[n + 1];
@@ -170,7 +171,9 @@ class Solution {
         }
         //当和为0时，组合的个数为0
         dp[0] = 0;
+        // 遍历物品
         for (int i = 1; i * i <= n; i++) {
+            // 遍历背包
             for (int j = i * i; j <= n; j++) {
                 if (dp[j - i * i] != max) {
                     dp[j] = Math.min(dp[j], dp[j - i * i] + 1);
@@ -180,6 +183,28 @@ class Solution {
         return dp[n];
     }
 }
+
+class Solution {
+    // 版本二， 先遍历背包, 再遍历物品
+    public int numSquares(int n) {
+        int max = Integer.MAX_VALUE;
+        int[] dp = new int[n + 1];
+        // 初始化
+        for (int j = 0; j <= n; j++) {
+            dp[j] = max;
+        }
+        // 当和为0时，组合的个数为0
+        dp[0] = 0;
+        // 遍历背包
+        for (int j = 1; j <= n; j++) {
+            // 遍历物品
+            for (int i = 1; i * i <= j; i++) {
+                dp[j] = Math.min(dp[j], dp[j - i * i] + 1);
+            }
+        }
+        return dp[n];
+    }
+}
 ```
 
 Python：
@@ -187,7 +212,7 @@ Python：
 ```python3
 class Solution:
     def numSquares(self, n: int) -> int:
-        '''版本一'''
+        '''版本一，先遍历背包, 再遍历物品'''
         # 初始化
         nums = [i**2 for i in range(1, n + 1) if i**2 <= n]
         dp = [10**4]*(n + 1)