From a64e11b09ad66f4a1ea22cdc3603e5cde85d88ef Mon Sep 17 00:00:00 2001
From: jinbudaily <18336218010@163.com>
Date: Tue, 18 Jul 2023 15:13:42 +0800
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---
 ...0019.删除链表的倒数第N个节点.md | 39 ++++++++++++-------
 1 file changed, 24 insertions(+), 15 deletions(-)

diff --git a/problems/0019.删除链表的倒数第N个节点.md b/problems/0019.删除链表的倒数第N个节点.md
index 84eac96b..1c95ad5b 100644
--- a/problems/0019.删除链表的倒数第N个节点.md
+++ b/problems/0019.删除链表的倒数第N个节点.md
@@ -7,7 +7,7 @@
 
 
 
-## 19.删除链表的倒数第N个节点
+# 19.删除链表的倒数第N个节点
 
 [力扣题目链接](https://leetcode.cn/problems/remove-nth-node-from-end-of-list/)
 
@@ -31,11 +31,13 @@
 输入：head = [1,2], n = 1
 输出：[1]
 
+## 算法公开课
+
+**[《代码随想录》算法视频公开课](https://programmercarl.com/other/gongkaike.html)：：[链表遍历学清楚！ | LeetCode：19.删除链表倒数第N个节点](https://www.bilibili.com/video/BV1vW4y1U7Gf)，相信结合视频再看本篇题解，更有助于大家对链表的理解。**
+
 
 ## 思路
 
-《代码随想录》算法公开课：[链表遍历学清楚！ | LeetCode：19.删除链表倒数第N个节点](https://www.bilibili.com/video/BV1vW4y1U7Gf)，相信结合视频在看本篇题解，更有助于大家对链表的理解。
-
 
 双指针的经典应用，如果要删除倒数第n个节点，让fast移动n步，然后让fast和slow同时移动，直到fast指向链表末尾。删掉slow所指向的节点就可以了。
 
@@ -93,7 +95,7 @@ public:
 
 ## 其他语言版本
 
-java:
+### Java:
 
 ```java
 public ListNode removeNthFromEnd(ListNode head, int n){
@@ -120,7 +122,8 @@ public ListNode removeNthFromEnd(ListNode head, int n){
 }
 ```
 
-Python:
+### Python:
+
 ```python
 # Definition for singly-linked list.
 # class ListNode:
@@ -151,7 +154,8 @@ class Solution:
         return dummy_head.next
 
 ```
-Go:
+### Go:
+
 ```Go
 /**
  * Definition for singly-linked list.
@@ -178,7 +182,7 @@ func removeNthFromEnd(head *ListNode, n int) *ListNode {
 }
 ```
 
-JavaScript:
+### JavaScript:
 
 ```js
 /**
@@ -198,7 +202,7 @@ var removeNthFromEnd = function(head, n) {
     return ret.next;
 };
 ```
-TypeScript:
+### TypeScript:
 
 版本一（快慢指针法）：
 
@@ -263,7 +267,7 @@ function removeNthFromEnd(head: ListNode | null, n: number): ListNode | null {
 };
 ```
 
-Kotlin:
+### Kotlin:
 
 ```Kotlin
 fun removeNthFromEnd(head: ListNode?, n: Int): ListNode? {
@@ -284,7 +288,8 @@ fun removeNthFromEnd(head: ListNode?, n: Int): ListNode? {
 }
 ```
 
-Swift：
+### Swift：
+
 ```swift
 func removeNthFromEnd(_ head: ListNode?, _ n: Int) -> ListNode? {
     if head == nil {
@@ -309,8 +314,8 @@ func removeNthFromEnd(_ head: ListNode?, _ n: Int) -> ListNode? {
 }
 ```
 
+### PHP:
 
-PHP:
 ```php
 function removeNthFromEnd($head, $n) {
     // 设置虚拟头节点
@@ -332,7 +337,8 @@ function removeNthFromEnd($head, $n) {
     }
 ```
 
-Scala:
+### Scala:
+
 ```scala
 object Solution {
   def removeNthFromEnd(head: ListNode, n: Int): ListNode = {
@@ -356,7 +362,8 @@ object Solution {
 }
 ```
 
-Rust:
+### Rust:
+
 ```rust
 impl Solution {
     pub fn remove_nth_from_end(head: Option<Box<ListNode>>, mut n: i32) -> Option<Box<ListNode>> {
@@ -377,7 +384,8 @@ impl Solution {
     }
 }
 ```
-C语言
+### C：
+
 ```c
 /**c语言单链表的定义
  * Definition for singly-linked list.
@@ -412,7 +420,8 @@ struct ListNode* removeNthFromEnd(struct ListNode* head, int n) {
 
 ```
 
-C#：
+### C#：
+
 ```csharp
 public class Solution {
     public ListNode RemoveNthFromEnd(ListNode head, int n) {