Merge pull request #1625 from jishan7/master

530.二叉搜索树的最小绝对差 python迭代法没有取abs
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程序员Carl
2022-09-07 09:15:14 +08:00
committed by GitHub

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@ -233,7 +233,7 @@ class Solution:
else: # 逐一处理节点 else: # 逐一处理节点
cur = stack.pop() cur = stack.pop()
if pre: # 当前节点和前节点的值的差值 if pre: # 当前节点和前节点的值的差值
result = min(result, cur.val - pre.val) result = min(result, abs(cur.val - pre.val))
pre = cur pre = cur
cur = cur.right cur = cur.right
return result return result